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3 years ago

6

HURRY QUICKLY PLEASE William measures the length of three sides of a building. Place the lengths in order from greatest to least

.
0.096 kilometers

2,100 cm

104 meters

1 answer:

insens350 [35]3 years ago

4 0

Answer:

104m, 0.096km, 2100cm

Step-by-step explanation:

0.096 kilometres = 9600

2100 cm

104m = 10400 cm

10400, 9600, 2100

104m, 0.096km, 2100cm

Answered by Gauthmath

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The sum of 3 consecutive even integers is 18<br>

larisa [96]

Answer:

4,6,8

Step-by-step explanation:

Let x = 1st even integer

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x+4 =3nd even integer

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Combine like terms

3x+6 = 18

Subtract 6 from each side

3x+6-6=18-6

3x= 12

Divide by 3

3x/3 =12/3

x = 4

x+2 = 6

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3 years ago

Jasmine took a cab home from her office. The cab charged a flat fee of $4, plus $2 per mile. Jasmine paid $32 for the trip. How

vaieri [72.5K]

To solve, make an equation. The equation would be
$$32 = 4 + 2x$
x represents the miles driven
to solve, subtract 4 from each side of the equation.
$32-4 = 4-4 + 2x
The equation is now
$28 = 2x
Now you divide by 2 on each side.
$28 ÷ 2 = 2x ÷ 2
simplify
14 = x
The answer is 14 miles

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3 years ago

1. If m varies directly as v2 and m = 3, when v =2, calculate the value of m when v =9.<br> (3marks)

Salsk061 [2.6K]

Answer:

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3 years ago

The photo is clear now so what is answer to this question?

erik [133]

Answer:

x = 4

Step-by-step explanation: because 13 - 13 u cross them out and u get 17 subtract 13 and ounce u do them u get 4 so then now your left with x so u bring that down and then u get x = 4 hopefully i answered your question or answer have a nice day as well

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3 years ago

completa con las razones trigonométricas de cada triángulo rectángulo dado y encuentra el lado faltante aplicando el teorema de

Rus_ich [418]

primero vamos a calcular el lado faltante usando el teorema de pitagoras para poder obtener el lado faltante a

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a=52.68 m

teniendo el lado faltante podemos calcular las razones trigonometricas

$\sin (55)=\frac{85}{100}=0.85$ $\cos (55)=\frac{52.68}{100}=0.52$ $\tan (55)=\frac{85}{52.68}=1.61$

$\csc (55)=\frac{100}{85}=1.17$ $\sec (55)=\frac{100}{52.68}=1.89$ $\cot (55)=\frac{52.68}{85}=0.61$

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1 year ago