1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ziro4ka [17]
2 years ago
6

HURRY QUICKLY PLEASE William measures the length of three sides of a building. Place the lengths in order from greatest to least

.
0.096 kilometers

2,100 cm

104 meters
Mathematics
1 answer:
insens350 [35]2 years ago
4 0

Answer:

104m, 0.096km, 2100cm

Step-by-step explanation:

0.096 kilometres = 9600

2100 cm

104m = 10400 cm

10400, 9600, 2100

104m, 0.096km, 2100cm

Answered by Gauthmath

You might be interested in
Find the equation of the parable in general form by completing the square. Then, state its vertex
lora16 [44]
The parabola will show the vertex in the format: y-k = (x-h)^2, where the vertex point
lies at (h, k).
so \: for \:  {x}^{2}  + 2x - y + 3 = 0
let's first put it in "y =" standard format:
y =  {x}^{2}  + 2x + 3
Since we cannot get a perfect square out of this, we complete the square: a=1, b=2, c=3
(b/2)^2 = (2/2)^2 = 1, so
y =  {(x +1)}^{2} ...\: is \: y =  {x}^{2}  + 2x + 1
So there's +2 leftover, since 3-1=2; so:
y =  {(x + 1)}^{2}  + 2
Now we'll subtract the 2 from both sides to show our vertex:
y - 2 =  {(x + 1)}^{2}
where our vertex (h, k) is at (-1, 2)
6 0
3 years ago
What is the cost per pound of oranges according to the graph?
iris [78.8K]
Ma’am the answer is 8



Please finis
5 0
2 years ago
Read 2 more answers
Determine the horizontal vertical and slant asymptote y=x^2+2x-3/x-7
lilavasa [31]

Answer:

<h2>A.Vertical:x=7</h2><h2>Slant:y=x+9</h2>

Step-by-step explanation:

f(x)=\dfrac{x^2+2x-3}{x-7}\\\\vertical\ asymptote:\\\\x-7=0\qquad\text{add 7 to both sides}\\\\\boxed{x=7}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{x\left(1-\frac{7}{x}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{x\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{1-\frac{7}{x}}=\pm\infty\\\\\boxed{not\ exist}

slant\ asymptote:\\\\y=ax+b\\\\a=\lim\limits_{x\to\pm\infty}\dfrac{f(x)}{x}\\\\b=\lim\limits_{x\to\pm\infty}(f(x)-ax)\\\\a=\lim\limits_{x\to\pm\infty}\dfrac{\frac{x^2+2x-3}{x-7}}{x}=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x(x-7)}=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x^2-7x}\\\\=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{x^2\left(1-\frac{7}{x}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{1+\frac{2}{x}-\frac{3}{x^2}}{1-\frac{7}{x}}=\dfrac{1}{1}=1

b=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-1x\right)=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-\dfrac{x(x-7)}{x-7}\right)\\\\=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-\dfrac{x^2-7x}{x-7}\right)=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3-(x^2-7x)}{x-7}\\\\=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3-x^2+7x}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{9x-3}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{x\left(9-\frac{3}{x}\right)}{x\left(1-\frac{7}{x}\right)}

=\lim\limits_{x\to\pm\infty}\dfrac{9-\frac{3}{x}}{1-\frac{7}{x}}=\dfrac{9}{1}=9\\\\\boxed{y=1x+9}

8 0
3 years ago
How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
What does m represent in the equation y=mx+b? Please I need help with this
artcher [175]

Slope

Step-by-step explanation:

y=mx+b

y=slope+ y-intercept

8 0
2 years ago
Other questions:
  • - 5 – 8p = – 3p<br> What is the correct solution?
    15·2 answers
  • Rules for rational and irrational numbers
    10·1 answer
  • The following diagram shows the path of a planet around the Sun. Kepler discovered that _____.
    6·2 answers
  • What is the Sum of P an 3/4
    13·1 answer
  • Which rigid motion is verified below?"
    10·1 answer
  • 10 points. The diameters of two circles are in the ratio of 2:3. Find the area of the smaller circle if the area of the larger i
    11·1 answer
  • 3x - y = 9<br> Slope-intercept??
    9·1 answer
  • Quadrilateral PRST is transformed according to the rule (x, y) → (x + 9, y +4) to create quadrilateral P'R'S'T'.
    8·1 answer
  • 4) A bag of sweets has orange and red sweets in the ratio 2:3. The number of red sweets
    15·2 answers
  • Anyone knows the answer?????????????
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!