What we want to draw is the half closed interval:
I= [-5, 4) excluding 0,
as the union of 2 different intervals say a and b.
Let a be the interval containing the smallest value.
Then the smallest value of a is -5, and the largest possible value of a is 0, not included, if we want to write a as an interval, without "gaps", or "holes".
So a=[-5, 0)
similarly, b=(0, 4).
Answer: [-5, 4)=[-5, 0)∪(0, 4)
You must try to remove one of the unknown variables from the system by multiplying one in a way that when adding (or subtracting) one to another “makes it disappear” and so whatever value you get can be substituted back in to get the other unknown!
Answer:
(1,0)
Step-by-step explanation:
3x + 6y = 3
7x + 3y = 7
Multiply the second equation by -2
-2( 7x + 3y = 7)
-14x -6y = -14
Add this to the first equation to eliminate y
3x + 6y = 3
-14x -6y = -14
--------------------
-11 x = -11
Divide by -11
x = 1
Now find y
3x + 6y = 3
3 +6y = 3
Subtract 3 from each side
6y = 0
y =0
Answer:
x=1
Step-by-step explanation:
you would change it to 5x-4(-3x+5)=-3, because you put the info for the first equation into the second equation.
5x-4(-3x+5)=-3
5x+12x-20=-3
17x-20=-3
17x=17
x=1
Step-by-step explanation:
x-the initial number of coconuts
x=3y+1
2y=3z+1
2z=3×7+1=>z=11=>y=17=>x=52
