Believe it or not, :), the width of the ribbon needs to be known to get the right answer. If the ribbon had an infinitely small width the ribbon needed would just be the perimeter.
P=2(L+W)
P=2(12+15)
P=54 in
However an infinitely small width is not something that has any practical application. For example, if the width of the ribbon were 1/2 in.
P=2((L+1)+W)
P=2(16+12)
P=56 in So the perimeter increased by 2 in when the ribbon was only 1/2 in wide.
The "infinitely small" width and the perimeter of 54 in is only a decent approximation if the ribbon were a very thin string.
Answer:
24 with a remainder of 1
Step-by-step explanation
so first you have to bring down the 3 so it is next to the six, and then you divide 36 by 15 and that equals 2. So you right a 2 on top. Then you have to multiply 2 and 15 and that equals 30 so you put a 30 below the 36. After you subtract, it equals 6 then you bring down the 1. Now you divide 61 and 15. The answer is 4 so you put a 4 on top next to the 2. After that you multiply 15 by 4 and that equals 60. You subtract 60 from 61, and you are left with a remainder of 1
x = [-(-6) +/- sqrt((-6)^2 - 4*1 * 8))] / 2
= (6 + sqrt4) / 2 , ( 6 - sqrt4)/2
= 4 , 2
Answer:
quizlet probably has your answer
Step-by-step explanation:
Step-by-step explanation:
Considering speed of Noha = 4miles per hour
and speed of andrew = 2 miles/hour
The distance between Noha and andrew = 15 miles
Case 1: when they are travelling towards each other( opposite direction)
Then their relative speed becomes = 4+2 = 6miles/hour
Time taken to meet = Distance/relative speed = 15/6 = 2.5 hours
Case2: When they are travelling same direction
Then their relative speed becomes = 4-2 = 2 miles/hour
Time taken to meet = Distance/ relative speed = 15/2 = 7.5 hours
