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Evgesh-ka [11]
3 years ago
7

Which point is a reflection of T(-6.5, 1) across the x-axis and the y-axis? A. point U B. point V C. point W D. point X

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0

Hey there! :)

Answer:

Point V.

Step-by-step explanation:

Given the coordinates of T at (-6.5, 1), U represents T before any reflections. (Helps to visualize this better)

Reflecting across the x-axis results in the sign of the y-coordinate changed. Point T after this reflection becomes (-6.5, -1).

Finally, reflecting across the y-axis will change the sign for the x-coordinate.

(-6.5, -1) becomes (6.5, 1). This is represented by point V.

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Javier had $305 in his bank account. His bank charges a monthly fee of $7.50.
EastWind [94]

Answer:

$282.50

Step-by-step explanation:

He will be charged $7.50 for 3 months, which is a total of 7.5 * 3 = $22.50.

Subtract this from the amount in his account to find the amount of money he has at the end of the three months:

305 - 22.5 = 282.5

The answer is therefore $282.50.

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Let m = 6x +5.<br> Which equation is equivalent to (6x + 5)^2 – 10 = -18x – 15 in terms of m?
aev [14]

Answer: m² + 3m - 10 = 0

Step-by-step explanation:

From the expression, considering

6x + 5 = m

The original expression

( 6x + 5 )² - 10 = -18 - 15

Factorize the right hand expression,

-18 - 15 = -3( 6x - 15 )

Since m = 6x + 5 , we now substitute for m in that expression

m² - 10 = -3m

Now re arrange the equation in the form,

ax² - bx + c = 0

Now back to the equation,

m² + 3m - 10 = 0,

So the equivalent equation will be

m² + 3m - 10 = 0

7 0
3 years ago
Which expression is equivalent to StartFraction 2 a + 1 Over 10 a minus 5 Endfraction divided by StartFraction 10 a Over 4 a squ
const2013 [10]

Answer:

\frac{(2a + 1)^2}{50a}

Step-by-step explanation:

Given

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

Required

Find the equivalent

We start by changing the / to *

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

\frac{2a + 1}{10a - 5} * \frac{4a^2 - 1}{10a}

Factorize 10a - 5

\frac{2a + 1}{5(2a - 1)} * \frac{4a^2 - 1}{10a}

Expand 4a² - 1

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1}{10a}

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1^2}{10a}

Express (2a)² - 1² as a difference of two squares

Difference of two squares is such that: a^2- b^2= (a+b)(a-b)

The expression becomes

\frac{2a + 1}{5(2a - 1)} * \frac{(2a - 1)(2a + 1)}{10a}

Combine both fractions to form a single fraction

\frac{(2a + 1)(2a - 1)(2a + 1)}{5(2a - 1)10a}

Divide the numerator and denominator by 2a - 1

\frac{(2a + 1)((2a + 1)}{5*10a}

Simplify the numerator

\frac{(2a + 1)^2}{5*10a}

\frac{(2a + 1)^2}{50a}

Hence,

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1} = \frac{(2a + 1)^2}{50a}

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0.1 or 1/10 is in simplest form

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