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3 years ago

Identify any solutions to the system given below.

Mathematics

2 answers:

fiasKO [112]3 years ago

3 0

Answer:
• (6, -7)
• (-4, 13)

Explanation:

• Option One

2x + y = 5
2(6) + (-7) = 5
12 - 7 = 5
5 = 5 {true}

3y = 15 - 6x
3(-7) = 15 - 6(6)
-21 = 15 - 36
-21 = -21 {true}

• Option Two

2x + y = 5
2(2) + 1 = 5
4 + 1 = 5
5 = 5 {true}

3y = 15 - 6x
3(1) = 15 - 6(2)
3 = 15 - 12
3 = 13 {not true}

• Option Three

2x + y = 5
2(-2) + (-9) = 5
-4 - 9 = 5
-13 = 5 {not true}

3y = 15 - 6x
3(-9) = 15 - 6(-2)
-27 = 15 + 12
-27 = 27 {not true}

• Option Four

2x + y = 5
2(-4) + 13 = 5
-8 + 13 = 5
5 = 5 {true}

3y = 15 - 6x
3(13) = 15 - 6(-4)
39 = 15 + 24
39 = 39 {true}

telo118 [61]3 years ago

3 0

Answer:

(6, -7)

(2, 1)

(-4, 13)

Step-by-step explanation:

2х + y = 5 ⇒ y= 5-2x

Зу = 15 – 6х ⇒ y= 5-2x

Both equations are same so any point satisfying one of them is the solution.

(6, -7)

-7= 5-12 - yes

(2, 1)

1= 5- 4 - yes

(-2, -9)

-9= 5 + 4 - no

(-4, 13)

13= 5+8- yes

So 3 of given points satisfy the equation

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NISA [10]

The correct question is;

Joey borrows $2400 from his grandfather and pays the money back in monthly payments of $200.

a. Write a linear function that represents the remaining money owed L(x) after x months.

b. Evaluate L(10) and interpret the meaning in the context of this problem.

A) L(x) = 200x + 2400; L(10) = 4400, This represents the amount Joey still owes his

grandfather after 10 months.

B) L(x) = -200x + 2400; L(10) = 400, This represents the amount Joey has paid his

grandfather after 10 months.

C) L(x) = 200x + 2400; L(10) = 4400, This represents the amount Joey has paid his

grandfather after 10 months.

D) L(x) = -200x + 2400; L(10) = 400, This represents the amount Joey still owes his

grandfather after 10 months.

Answer:

A) L(x) = 2400 - 200x

B) Option D is correct

Step-by-step explanation:

A) We are told that Joey borrowed 2400.

Now he pays back in installments of 200 every month.

Thus for x number of months he would have paid 200x.

Thus,the linear function that represents the remaining money owed is;

L(x) = 2400 - 200x

B) L(10) = 2400 - (200 * 10)

L(10) = 2400 - 2000

L(10) = 400

Thus, after 10 months, Joey is owing 400.

So, looking at the given options, the correct one is option D.

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3 years ago

Learning Task 1 4/625 11. 796 A. Simplify the radical expressions 1. V63 6. V24 2. 48 7. 781 3. 775 8. V128 4. 99 9. 340 5. 92 1

kompoz [17]

Question:

Simplify the radical expressions

$1.\ \sqrt{63$ $2.\ \sqrt{48$ $3.\ \sqrt{75$ $4.\ \sqrt{99$ $5.\ \sqrt{92$

$6.\ \sqrt[3]{24}$ $7.\ \sqrt[3]{81}$ $8.\ \sqrt{128}$ $9.\sqrt[3]{40}$ $10.\ \sqrt[3]{135}$

Answer:

$\sqrt{63}= 3 \sqrt7$

$\sqrt{48} = 4\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$\sqrt{99} = 3 \sqrt{11$

$\sqrt{92} = 2\sqrt{23$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$\sqrt{128} = 8 \sqrt{2}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

Step-by-step explanation:

$1.\ \sqrt{63$

Express 63 as 9 * 7

$\sqrt{63}= \sqrt{9 * 7$

Split:

$\sqrt{63}= \sqrt{9} * \sqrt7$

$\sqrt{63}= 3 * \sqrt7$

$\sqrt{63}= 3 \sqrt7$

$2.\ \sqrt{48$

Express 48 as 16 * 3

$\sqrt{48} = \sqrt{16*3}$

Split

$\sqrt{48} = \sqrt{16}*\sqrt{3}$

$\sqrt{48} = 4*\sqrt{3}$

$\sqrt{48} = 4\sqrt{3}$

$3.\ \sqrt{75$

Express 75 as 25 * 3

$\sqrt{75} = \sqrt{25*3}$

Split

$\sqrt{75} = \sqrt{25}*\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$4.\ \sqrt{99$

Express 99 as 9 * 11

$\sqrt{99} = \sqrt{9} * \sqrt{11}$

Split

$\sqrt{99} = 3 \sqrt{11$

$5.\ \sqrt{92$

Express 92 as 4 * 23

$\sqrt{92} = \sqrt{4} * \sqrt{23$

$\sqrt{92} = 2* \sqrt{23$

$\sqrt{92} = 2\sqrt{23$

$6.\ \sqrt[3]{24}$

Express 24 as 8 * 3

$\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}$

Express 8 as 2^3

$\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$7.\ \sqrt[3]{81}$

Express 81 as 27 * 3

$\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}$

Express 27 as 3^3

$\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$8.\ \sqrt{128}$

Express 128 as 64 * 2

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

$9.\sqrt[3]{40}$

Express 40 as 8 * 5

$\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}$

$\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$10.\ \sqrt[3]{135}$

Express 135 as 27 * 5

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

Express 27 as 3^3

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

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3 years ago

Given the set of numbers, 2, 3, 4, 8, 10 with mean = 6 The Second moment about the mean for this set is?

Rufina [12.5K]

Answer:

Given,

2,3,4,8,10

ex=2+3+4+8+10+x

=27+x

mean=6

no of data=5

now,

mean = ex/n

or,6=27+x/5

or,5×6=27+x

or,30=27+x

or,30-27=x

3=x

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3 years ago