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Ira Lisetskai [31]
3 years ago
14

When you move a paragraph in a document that includes text with a footnote, what happens to the footnote reference?

Computers and Technology
1 answer:
andrey2020 [161]3 years ago
4 0
<h2>Answer:</h2>

Moving a paragraph with a footnote, The footnote moves along with it. the condition is that you have entered the footnote in the following manner.

Reference → Insert footnote  

This way whether the content has been copy/pasted or crop/pasted the footnote moves along.

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What is the difference between HTML and XML?
Luba_88 [7]

Explanation:

HTML displays data and describe the structure of a webpage while XML stores and transfers data.

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2 years ago
A UI text element must be added to ______.an empty background container game objecta prefaba slot game objecta tray objecta canv
barxatty [35]

Answer:

canvas

Explanation:

The answer to this question is that A UI text element must be added to a canvas. The canvas is that area that all the unity items (UI) have to be inside.

We insert the Text UI element when we move to the hierarchy of the scene from create we move to UI and then to text.

After all these have been done, we will get a text element which have been added in the Canvas region.

5 0
2 years ago
Decrypt this message: P ht uva h zwf
KatRina [158]
Translation: I am a spy
5 0
3 years ago
If there are 8 opcodes and 10 registers, a. What is the minimum number of bits required to represent the OPCODE? b. What is the
Nimfa-mama [501]

Answer:  

For 32 bits Instruction Format:

OPCODE   DR               SR1                   SR2      Unused bits

a) Minimum number of bits required to represent the OPCODE = 3 bits

There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.

Ceil (log2 (8)) = 3

b) Minimum number of bits For Destination Register(DR) = 4 bits

There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value.  4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.  

Ceil (log2 (10)) = 4

c) Maximum number of UNUSED bits in Instruction encoding = 17 bits

Total number of bits used = bits used for registers + bits used for OPCODE  

     = 12 + 3 = 15  

Total  number of bits for instruction format = 32  

Maximum  No. of Unused bits = 32 – 15 = 17 bits  

OPCODE                DR              SR1             SR2              Unused bits

  3 bits              4 bits          4 bits           4 bits                17 bits

7 0
3 years ago
2. Consider the two-dimensional array A: int A[][] = new int[100][100]; where A[0][0] is at location 200 in a paged memory syste
bogdanovich [222]

Answer:

Check the explanation

Explanation:

An integer (int) is of two different bytes and each page has 200 bytes in length. What this means is that each row of array A (100 int) will fits perfectly in a page.

(a) For the initial or first array-initialization loop, one column is processed at a time, so a page fault will be generated at every inner loop iteration, with a total of 100*100=10,000 page faults.

(b)  And when it comes to the second array-initialization loop, one row is processed at a time, and a page fault is generated at every outer loop iteration, with a total of 100 page faults.

Hence second array-initialization loop, has better spatial locality.

6 0
3 years ago
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