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lesya [120]
3 years ago
9

Sam’s password is known to be formed of 3 decimal digits (0-9) in a given order. Karren and Larry are attempting to determine Sa

m’s password by testing all possible combinations. If they are only able to try 10 combinations every day, how many days would it take to try all the possible combinations? 1000 100 3 73
Computers and Technology
2 answers:
prohojiy [21]3 years ago
7 0

Answer:

100

Explanation:

mezya [45]3 years ago
4 0

Answer:

The answer is 100, hope this helps!

Explanation:

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The answer is student loans
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Read 2 more answers
Write a program that helps a young student learn to make change. Use the random number generator to generate change amounts betw
erastovalidia [21]

Answer:

#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

 

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

 

int quarters = coins/25;

 

coins = coins%25;

 

int dimes = coins/10;

 

coins = coins%10;

 

int nickles = coins/5;

coins = coins%5;

 

int pennies = coins/1;

 

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

 

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

 

}

 

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

 

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

 

int quarters = coins/25;

 

coins = coins%25;

 

int dimes = coins/10;

 

coins = coins%10;

 

int nickles = coins/5;

coins = coins%5;

 

int pennies = coins/1;

 

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

 

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

 

}

 

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}

Explanation:

  • Use the built-in rand function to generate a random coin.
  • Get all the required values for quarters, dimes, nickles and pennies and store them in variables.
  • Check if the coins give a value of temp, then answer is correct and the values of user will be added.
  • Optimum solution is displayed  If it does not matches with the optimum solution. Display that the answer is wrong along with solution.
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In early Oklahoma, __________ tribes were most nomadic. A. hunting B. farming C. semi-sedentary D. agricultural Please select th
denpristay [2]

Answer:

A

Explanation:

They needed to follow the food/buffalo

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2 years ago
Dharma opens one window, does a little work, closes the window and then opens a new one. Instead of opening windows, what can Dh
seraphim [82]

Answer:

Make a goal

Explanation:

She could make a goal achieve it and reward herself. Do this multiple times and she will be done

5 0
3 years ago
Write two recursive versions of the function minInArray. The function will be given a sequence of elements and should return the
Viktor [21]

Answer:

Following are the code to this question:

#include <iostream>//defining header file

using namespace std;//using namespace

int minInArray1(int arr[],int arrSize)//declaring method minInArray1

{

if(arrSize == 1)//use if block to check arrSize value is equal to 1  

{

return arr[0];//return first element of array

}

else //defining else block

{

int max= minInArray1(arr, arrSize-1);//use integer variable max to call method recursively  

if(arr[arrSize-1] < max)//use if block to check array value  

{

max = arr[arrSize-1];//use max to hold array value

}

return max;//return max variable value

}

}

int minInArray2(int arr[], int low, int high)//defining a method minInArray2  

{

if(low == high) //use if to check low and high variable value are equal

{

return arr[low];//return low variable value

}

else //defining else block

{

int minimum = minInArray2(arr, low+1, high);//defining integer variable minimum to call method minInArray2 recursively

if(arr[low] < minimum)

{

minimum = arr[low];//use minimum variable to hold array value

}

return minimum;//return minimum value

}

}

int main()//defining main method

{

int arr[10] = { 9, -2, 14, 12, 3, 6, 2, 1, -9, 15 };//defining an array arr

int r1, r2, r3, r4;//defining integer variable

r1 = minInArray1(arr, 10);//use r1 variable to call minInArray1 and hold its return value

r2 = minInArray2(arr, 0, 9);//use r1 variable to call minInArray2 and hold its return value

cout << r1 << " " << r2 << endl; //use print method to print r1 and r2 variable value

r3 = minInArray2(arr, 2, 5);//use r3 variable to call minInArray1 and hold its return value

r4 = minInArray1(arr + 2, 4); //use r4 variable to call minInArray2 and hold its return value

cout<<r3<< " " <<r4<<endl; //use print method to print r3 and r4 variable value

return 0;

}

Output:

please find the attached file.

Explanation:

In the given code two methods, "minInArray1 and minInArray2" is defined,  in the "minInArray1" it accepts two-variable "array and arrSize" as the parameter, and in the "minInArray2" method it accepts three integer variable "array, low, and high" as the parameter.

  • In the "minInArray1" method, and if the block it checks array size value equal to 1 if the condition is true it will return the first element of the array, and in the else block the max variable is defined, that calling method recursively
  • and store its value.
  • In the "minInArray2" method, an if the block it checks low and high variable value is equal. if the condition is true it will return a low array value. In the next step, the minimum value is defined, which checks the element of the array and uses a low array to store its value.
  • In the main method an array and four integer variable "r1, r2, r3, and r4" is defined, which calls two methods "minInArray1 and minInArray2" and use print method to print its value.
7 0
3 years ago
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