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aniked [119]
2 years ago
15

The volume of an oblique pyramid with a square base is V units3 and the height is h units.Which expression represents the area o

f the base of the pyramid?
a) 3 v/h unils^2
b) (3 v - h)unils^2
c) (v - 3 h)unils^2
d) v/3h unils^2
Mathematics
2 answers:
melamori03 [73]2 years ago
7 0

Answer: a) \dfrac{3V}{h}\ units^2

Step-by-step explanation:

We know that the volume of an oblique pyramid is given by :-

\text{Volume}=\dfrac{1}{3}\text{(Base Area x height) }

If the volume of an oblique pyramid with a square base is V units³ and the height is h units.

Then, we have

V=\dfrac{1}{3}\text{(Base Area x h) }

Multiply 3 on both sides , we get

3V=\text{(Base Area x h) }

Divide both sides by h , we get

\dfrac{3V}{h}=\text{Base Area }

i.e. \text{Base Area }=\dfrac{3V}{h}\ units^2

Hence, the expression represents the area of the base of the pyramid = \dfrac{3V}{h}\ units^2

Hence, the correct answer is a) 3 v/h units^2

ser-zykov [4K]2 years ago
7 0

Answer:

A on edge 2020

Step-by-step explanation:

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What is the equation of the line that passes through the point (6,14) and is parallel to the line with the following equation? y
Gekata [30.6K]

Answer:

y=\displaystyle-\frac{4}{3}x+22

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept
  • Parallel lines always have the same slope (<em>m</em>)

<u>Determine the slope (</u><em><u>m</u></em><u>):</u>

<u />y=\displaystyle-\frac{4}{3}x -1<u />

The slope of the given line is \displaystyle-\frac{4}{3}, since it is in the place of <em>m</em> in y=mx+b. Because parallel lines always have the same slope, the slope of a parallel line would also be \displaystyle-\frac{4}{3}. Plug this into y=mx+b:

y=\displaystyle-\frac{4}{3}x+b

<u>Determine the y-intercept (</u><em><u>b</u></em><u>):</u>

y=\displaystyle-\frac{4}{3}x+b

To find the y-intercept, plug in the given point (6,14) and solve for <em>b</em>:

14=\displaystyle-\frac{4}{3}(6)+b\\\\14=-8+b\\b=22

Therefore, the y-intercept of the line is 22. Plug this back into y=\displaystyle-\frac{4}{3}x+b:

y=\displaystyle-\frac{4}{3}x+22

I hope this helps!

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MA_775_DIABLO [31]

Answer:

D

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch
kykrilka [37]
Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle. 

Thus, half the angle formed by the chord at the centre of the circle is given by:

\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2}  \\  \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o

Now, 

\sin60^o= \frac{9}{r}  \\  \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392

Therefore, the radius of the circle is 10.4 cm to 1 d.p.


Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o

Now, 

\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm


Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

\sin40^o= \frac{y}{10}  \\  \\  \\ \Rightarrow y=10\sin40^o=6.428

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.
3 0
3 years ago
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