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hichkok12 [17]
3 years ago
15

Which is colder 0°F or 6°F

Mathematics
1 answer:
pochemuha3 years ago
5 0
Because 6 is greater than 0, so 0F would be colder.
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What set would no longer be a A function if the ordered pair(5,3) was added
Delicious77 [7]
The answer is D because a function means for every input  you get exactly one output so
for every x you get one y
in D there is a coordinate (5,2) meaning that if you put in 5 for x you get 2 for y

but the new ordered pair also  has 5 for x but has a difarent y value.  this violates the definition of a funciton
4 0
3 years ago
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PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B
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Answer:

Step-by-step explanation:

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3 years ago
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Given ​ f(x) = x^2 + 14x + 40 ​. Enter the quadratic function in vertex form in the box. f(x)=
finlep [7]
Recall that the vertex form of a quadratic function (or parabolic function) is equal to

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One concept that we must remember when completing the square is that

(a + b)² = a² + 2ab + b²

So, to complete the square for (x² + 14x + ____), we have 2ab = 14 where a = 1. Thus, b = 14/2 = 7. Hence, the last term of the perfect square must equal to 7² = 49.

So, going back to the function, we have

f(x) = (x^{2} + 14x + 40 + 0)
f(x) = (x^{2} + 14x + 40 + 49 - 49)
f(x) = (x^{2} + 14x + 49) + 40 - 49
f(x) = (x + 7)^{2} - 9

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Answer: f(x) = (x + 7)² - 9
6 0
3 years ago
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krok68 [10]

Answer:

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Step-by-step explanation:

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Fudgin [204]

Answer:

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Step-by-step explanation:

I calculated it logically

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