1. Any number above 13 works. Why? Because 20-7=13, and to be greater than 20, you must add a number larger than 13.
Examples: 14+7 > 20, 30+7 > 20, 100+7 > 20
2. Any number below 25/3 (which is also 8.3 with a repeating 3) works. Why? Because 25/3=8.3 with a repeating 3, and to remain less than 25, you must multiply by a number less than 8.3 with a repeating 3.
Examples: 3(8) < 25, 3(5) < 25, 3(0) < 25
3. 4 buses. 1 bus will hold 60 students, 2 will hold 120, 3 will hold 180, and 4 will hold 240. The question is trying to trick you into putting now 3.3333333333... buses because that's what 200/60 is, but there is no such thing as a third of a bus. So you need at least 4 buses. (There will be an extra 40 spaces for passengers on the 4th bus, but that is okay.)
To find this answer I did 200/60 and got 3.3 with a repeating 3. You must round to the higher whole number. Rounding down to 3 buses leaves you with 20 students without a bus.
4. 19 boxes. 18 boxes will only hold 288 candies. The question is trying to trick you into putting down 18.75 boxes because that's what 300/16 is, but there is no such thing as 75% of a box. So you need at least 19 boxes. (There will be an extra 4 spaces for candies in the 19th box, but that is okay.)
To find this answer I did 300/16 and got 18.75. You must round to the higher whole <span>number. Rounding down to 18 boxes leaves you with 12 candies without a box.</span>
Answer:
3.5 hours
Step-by-step explanation:
Ediburgh -------------------------------350 miles-------------------------London
Let the distance traveled by train from Edin to London be "x"
hence the distance traveled by train from London to Edin would be "350-x"
- The rate of Edin to London train is 60
- The rate of London to Edin train is 40
Let the time they meet be"t"
Now, we know distance formula to be D = RT
Where
D is distance
R is rate
and
T is time
<u>Train from Edin to London:</u>
x = 60t
<u>Train from London to Edin:</u>
350-x = 40t
Solving for x:
350 - 40t = x
We put this into first equation:
x = 60t
350 - 40t = 60t
350 = 100t
t = 350/100
t = 3.5
They meet after 3.5 hours
By running in a bearing of 127°, Paul motion is in the south eastern direction.
Correct responses:
a. Please find attached the required diagram created with MS Visio
b. Paul's distance travelled east is approximately 11.98 km
- Paul's distance travelled south is approximately 0.903 km
<h3>Method used for diagram and for the distance calculation</h3>
Given:
The distance Paul runs = 1.5 km
The bearing Paul is running = 127°
a. The bearing of path Paul runs, 127°, is the angle measured in the clockwise direction relative to the northern direction
Please find attached the diagram representing the situation, created with MS Visio.
b. Paul's distance travelled east relative to the starting point is given by the component of Paul's path in the x-axis direction which is found as follows;
- Paul's distance east = 15 km × cos(37°) ≈ <u>11.98 km</u>
Pau's distance travelled in the south direction relative to the starting point
is given by the vertical distance travelled relative to the x-axis, which is
given as follows;
Distance Paul travels south = 1.5 km × sin(37°) ≈ <u>0.903 km</u>
Learn more about bearings in trigonometry here:
brainly.com/question/23427938
Answer:
132 degrees.
Step-by-step explanation:
Let the supplement be x and the angle be y.
x + y = 180 degrees.
y = (3x - 12) degrees.
x + 3x - 12 = 180
4x = 192
x = 48 degrees
y = 132 degrees
Hope this helped!
