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katrin2010 [14]
3 years ago
10

This is a continuation of the previous exercise. For each set of input parameters, plot the forcing function and the particular

solution on the same chart, with an appropriate title. The tricky part here is that the scale of the response (particular solution f(t)) can be very different than the forcing function, so one might easily dwarf the other. One way to fix this is to scale the response by some factor of 10. To find the appropriate factor of 10, use this line of code:___________.
Mathematics
1 answer:
Oxana [17]3 years ago
6 0

Answer: 10 x 10

Step-by-step explanation:

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Which statements are true about 5/6 and 7/10 check all that apply​
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Answer:

<em>(1) 40 is a common multiple of 6 and 10 </em>

False:

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Multiples of 10: 10, 20, 30, 40...

<em>(2) The fraction 5/6 is greater than 7/10</em>

True:

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<em>(3) The fraction 42/60 is an equivalent form of 7/10</em>

True:

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42/10 = 42/10 ∴ 7/10 = 42/10

<em>(4) The only value that can be used as a common denominator is 60</em>.

False:

While 60 is a plausible denominator, there are other denominators that can be used. Remember that what you do to the denominator, you do to the numerator.

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