Let's use the process of elimination:
We know the bottom two are incorrect, because numbers that are divisible by 9 ARE divisible by 3.
Take 18 for an example. 18 is divisible by 3 (3 * 6 = 18), and 9 (9*2 = 18).
Some of the numbers that are divisible by 9 are also divisible by 3 isn't the best statement, because we know that all multiples of 9 are divisible by 3.
Now we have 2 of them.
I think it's the second one, because the first one doesn't explain the details between the relationship of 9 and 3 (as well as the second one).,
So I think it's the second from the top.
(A number that is divisible by 9 is also divisible by 3, because all factors of 9, are factors of 3.)
Answer:
The value at the end of year 2 is $4400.
Step-by-step explanation:
The best approach here is to determine the expression for the line depreciation and then calculate the depreciation value at x = 2 years.
A line is given by
![y = mx + b](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20b)
where m is the slope and b the bias (aka y-intercept). You can determine both directly from what is given. The slope is change in y divided by change in x. We know that over 5 years the car loses (500-7000)=-6500 in value. So, the slope is m=-6500/5 (note the negative sign). At time 0, the y-intercept is 7000, since that is the initial value (at year 0). So our line function is fully identified:
![y = -\frac{6500}{5}x+7000](https://tex.z-dn.net/?f=y%20%3D%20-%5Cfrac%7B6500%7D%7B5%7Dx%2B7000)
and gives you the value of the car in any given year. To answer the question, we now plug in 2 as value of x:
![y=-\frac{6500}{5}\cdot 2 + 7000= 4400](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B6500%7D%7B5%7D%5Ccdot%202%20%2B%207000%3D%204400)
Any number greater than -8
You say that there is uniform acceleration so:
vf-vi=at (final velocity minus initial velocity is equal to acceleration times time)
We know vf, vi, and t so we can solve for acceleration:
24-12=a10
12=10a
a=1.2
That is the acceleration, we will need to integrate with respect to time twice...
v=⌠a dt
v=at+vi , we know a=1.2m/s^2 and vi=12m/s
v=1.2t+12,
x=⌠1.2t+12 dt
x=1.2t^2/2+12t+xo, we can just let xo=0 for this problem...
x(t)=0.6t^2+12t
Now we know that this acceleration lasts for 10 seconds so the distance traveled in that time is:
x(10)=0.6(10^2)+12(10)
x(10)=60+120
x(10)=180 meters
Answer: 12.56
Step-by-step explanation:
If I remember correctly, the equation for circumference is C=2r*pi (R representing radius). For this problem, if 2 is your radius 2R would equal 4. Take this number and multiply it by 3.14 (pi) to get your final answer.