Solution:
Number of wooden boards that Pierre possess= 220
Number of nails that Pierre have= 760
The two expression which represents the number of tables T and chairs C he can make with 220 wooden boards and 760 nails
1. 13 T+8 C≤220
2. 48 T+37 C≤760
We can solve it by two methods, either graphically or by finding their point of intersections,as these two are inequalities in two variable
Equation (1) × 37 - Equation (2) × 8
481 T + 296 C-384 T -296 C≤8140 - 6080
97 T ≤ 2060
T ≤ 21.23(approx)
Putting the value of T in equation (1),
13 × 21.23 + 8 C ≤ 220
347.80 + 8 C≤220
8 C ≤ 220 - 347.80
8 C≤-127.80
As, the value of Chairs (C) can't be negative.
So, the two inequalities which represents number of chairs and number of tables is incorrect.
So, we can't find total number of chairs and total number of tables with the given inequalities.
