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Alisiya [41]
3 years ago
9

A rectangular table with an area of 6 cubic yards and a length of 3 yards. what is its perimeter in inches

Mathematics
1 answer:
weqwewe [10]3 years ago
8 0
Area of rectangle = Width x Length
thus area of 6=W3 6/3=W 2=W

perimeter of rectangle is 2W + 2L
2×2 + 2×3 = 4+6 = 10 square yards

1 yard is 36 inches
thus, 10 yards × 36 inches/yard = 360
360 inches
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A club with 12 members is to choose three officers president vice-presidents and secretary-treasurer if each office is to be hel
lesya692 [45]

Answer:

12P3 = 1320

Step-by-step explanation:

How you need select three persons of a group of twelve persons, but in the selection each member of the group has a different position, then you need use a permutation

Permutation is defined how

nPr = \frac{n!}{(n-r)!}

In our case n = 12 and r = 3

Thus

12P3 = \frac{12!}{(12-3)!}

12P3 = 1320

6 0
3 years ago
Colin buys a car for £45500. It depreciates at a rate of 6% per year. How much will it be worth in 3 years? Give your answer to
natali 33 [55]

Answer:

yes

Step-by-step explanation:

the answer is 37,490.00 because over the span of 3 years the car would be worth 8,010.00 less

7 0
3 years ago
There are 6 paintings on three walls of a room. If annart gallery has 13 such rooms, how many paintings are there in its collect
SSSSS [86.1K]

Answer: (I think)

78 paintings

Step-by-step explanation:

6 x 13 = 78

3 0
4 years ago
Using the numbers 2,5,8, and 9 create a equation that equals 4
lbvjy [14]
9-8=1+5=6-2=4

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4 0
4 years ago
8.The weight distribution of parcels sent in a certain manner is normal with mean value 12lb and standard deviation 3.5 lb. The
Sladkaya [172]

Answer:

The value is c = 21.1445.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The weight distribution of parcels sent in a certain manner is normal with mean value 12lb and standard deviation 3.5 lb.

This means that \mu = 12, \sigma = 3.5

What value of c is such that 99% of all parcels are at least 1 lb under the surcharge weight?

This 1 added to the value of X for the 99th percentile, which is X when Z has a p-value of 0.99, so X when Z = 2.327.

Z = \frac{X - \mu}{\sigma}

2.327 = \frac{X - 12}{3.5}

X - 12 = 2.327*3.5

X = 20.1445

1 + 20.1445 = 21.1445

The value is c = 21.1445.

7 0
3 years ago
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