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Vilka [71]
2 years ago
5

Given log3 2=0.631 log3 7=1.771 what is log3 14?

Mathematics
2 answers:
Leni [432]2 years ago
5 0
In logarithm, inverse operations are applied.
log_3{14} =  log_3{7} +   log_3{14} \\ log_3{14} = 0.631 + 1.771 \\log_3{14} = 2.402
-BARSIC- [3]2 years ago
3 0

Answer:

2.402

Step-by-step explanation:

Given log_3 2=0.631

log_3 7=1.771

we need to find out log_3(14)

we know 14 = 7 * 2

log_3(14)=log_3(7*2)

Apply log property

log mn= log m + log n

log_3(7*2)=log_3(7) + log_3(2)

Plug in the given vales for log

log_3(7*2)=1.771 + 0.631)

= 2.402

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Answer:

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Step-by-step explanation:

It sounds like we are pretending A is the universe.  The only numbers in our world are 1,2,3,4, and 5.

You are given B is all numbers greater than 2.

The complement of B would all the elements not listed in B.

The elements in B are 3,4, and 5, since we are looking for numbers greater than 2 in our world of numbers above.

The elements not in B are 1 and 2.

So B complement is {1,2}.

There are 2 elements in our set for B complement. The elements that were counted were just the element 1 and the element 2.

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