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2 years ago

7

How many medians a triangle can have?

2 answers:

Serhud [2]2 years ago

8 0

Answer : It Is 3

Explanation : Medians Are The Line Segments That Divides A Side Of A Triangle Into Two Equal Parts, Each Having Equal Length. And Since Triangles Have 3 Sides, They Have 3 Medians As Well.

OverLord2011 [107]2 years ago

5 0

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Medians are the line segments that divides a side of Triangle into two equal parts, each having equal length. and since triangles have 3 sides, they have 3 medians as well.

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Y-1=-2(x+3) in standard form

romanna [79]

Answer:

2x + y + 5 = 0

Step-by-step explanation:

y − 1 = -2 (x + 3)

y − 1 = -2x − 6

2x + y + 5 = 0

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2 years ago

(a) The Feelgood Gym has a monthly membership fee of $100 and it charges an addi-

Ierofanga [76]

If I use the gym for x hours in a month, the total cost in terms of x will be 1000 + x.

a. Monthly membership fee = $100

Additional amount charged = $1 per hour.

If I use the gym for x hours in a month, the total cost in terms of x will be:

= 1000 + 1(x)

= 1000 + x

b. Also, if the amount charged is $35 per month and $3.50 per hour, the total cost will be:

= 35 + 3.50(x)

= 35 + 3.5x

c. The number of hours that will give same cost will be:

1000 + x = 35 + 3.5x

Collect like terms.

1000 - 35 = 3.5x - x

965 = 2.5x

x = 965/2.5

x = 386

In 386 hours, the total cost will be the same.

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2 years ago

If cos B is 4/5 what is sin a?

Keith_Richards [23]

Answer:

sin(A+B)=sinAcosB+cosAsinB. Putting the values in. sin(A+B)=(4/5)(−3/5)+(3/5)(−4/5). sin(A+B)=−24/25.

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2 years ago

3 (2x-4)=2 (x+4) solve the following problem

ratelena [41]

3(2x-4)=2(x+4)
6x-12=2x+8
6x-2x=8+12
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x=20/4
x=5

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3 years ago

Read 2 more answers

(1+cos2x)/(1-cos2x) = cot^2x

sesenic [268]

We will turn the left side into the right side.

$\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x$

Use the identity:

$\cos 2x = \cos^2 x - \sin^2 x$

$\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x$

$\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x$

Now use the identity

$\sin^2 x + \cos^2 x = 1$ solved for sin^2 x and for cos^2 x.

$\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x$

$\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x$

$\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x$

$\cot^2 x = \cot^2 x$

8 0

2 years ago