Answer:
C. 178−−−√ m
Step-by-step explanation:
Given the following :
v = final velocity (in m/s)
u = initial velocity (in m/s)
a = acceleration (in m/s²)
s = distance (in meters).
Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters
Using the 3rd equation of motion :
v^2 = u^2 + 2as
v^2 = 8^2 + 2(3)(19)
v^2 = 64 + 114
v^2 = 178
Take the square root of both sides :
√v^2 = √178
v = √178
Answer:
y= -69/8 (negative 69 over 8)
Step-by-step explanation:
First, you have to simplify both sides of the equation:

Second, add 3/4 to both sides:
-2/3y +-3/4 + 3/4=5 +3/4
-2/3y= 23/4
Next, multiply both sides by 3/(-2) (3 over -2)
(3/-2)*(-2/3y)= (3/-2) * (23/4)
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<em><u>y= -69/8</u></em>
My bests answer I got was a<3
f^-1(x)=(x-3)/4 is the inverse function f(x)=y=>y=4x+3 because f(x) is another way of writing y
Answer:
true
Step-by-step explanation: