Answer
Find out the value of x .
To proof
SAS congurence property
In this property two sides and one angle of the two triangles are equal.
in the Δ ADC and ΔBDC
(1) CD = CD (common side of both the triangle)
(2) ∠CDA = ∠ CDB = 90 °
( ∠CDA +∠ CDB = 180 ° (Linear pair)
as given in the diagram
∠CDA = 90°
∠ CDB = 180 ° - 90°
∠ CDB = 90°)
(3) AD = DB (as shown in the diagram)
Δ ADC ≅ ΔBDC
by using the SAS congurence property .
AC = BC
(Corresponding sides of the congurent triangle)
As given
the length of AC is 2x and the length of BC is 3x - 5 .
2x = 3x - 5
3x -2x =5
x = 5
The value of x is 5 .
Hence proved
25 kids in all
2xboys:3x girls
so the equation would be
2x+3x=25
solve,
5x=25
/5 /5
x=5
2x=10
3x=15
10 boys and 15 girls
9514 1404 393
Answer:
- 13 ft
- (a) 1 second; (b) t = 0, t = 1/2
Step-by-step explanation:
<h3>1. </h3>
Let w represent the length of the wire. Then the height of attachment is (w-1). The Pythagorean theorem tells us a relevant relation is ...
5² +(w -1)² = w²
w² -2w +26 = w² . . . . . . . eliminate parentheses, collect terms
26 = 2w . . . . . . . . . . . . add 2w
13 = w . . . . . . . . . . . . divide by 2
The length of the wire is 13 feet.
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<h3>2. </h3>
(a) When h = 0, the equation is ...
0 = -16t^2 +8t +8
Dividing by -8 puts this into standard form:
2t^2 -t -1 = 0
Factoring, we get ...
(2t +1)(t -1) = 0
The positive value of t that makes a factor zero is t = 1.
It will take 1 second for the gymnast to reach the ground.
__
(b) When h = 8, the equation is ...
8 = -16t^2 +8t +8
Subtract 8 and divide by 8 to get ...
0 = -2t^2 +t
0 = t(1 -2t) . . . . factor out t
Values of t that make the factors zero are ...
t = 0
t = 1/2
The gymnast will be 8 feet above the ground at the start of the dismount, and 1/2 second later.
Answer:
excusme where is the model
Step-by-step explanation:
Answer:
we have to find the quotient and the remainder when (x³ + 5x + 3x² + 5x³ + 3) is divided by (x² + 4x + 2) ♥9 dividend = x² + 4x + 2 using Euclid division lemma, x² + 4x + 2) x² + 5x³ + 3x² + 5x + 3(x³ - 4x² + 19x - 65 x² + 4x² + 2x³ - 4x² + 3x² + 3x² - 4x*-16x³8x² 19x³ + 11x² + 5x 19x³ +76x² + 38x -65x²-33x + 3 -65x²-260x - 130 +227x + 133 Therefore the quotient is x² - 4x + 19x - 65 and remainder is 227x + 133