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ser-zykov [4K]
3 years ago
11

A single die is rolled 100 times. list the probabilities below from least to greatest. p(odd), p(>4), p(prime), p(8)

Mathematics
1 answer:
dybincka [34]3 years ago
6 0
ALL OUTCOME {1,2,3,4,5,6}

Greater than 4 = {5,6}=======>P(>4) = 2/6 =1/3

Odd ={1,3,5} ==============> P(Odd) =3/6 =1/2

Prime ={1,2,3,5} ===========>P(prime) = 5/6

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Answer:

B

Step-by-step explanation:

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She spended $7.50 on each book- If the camp leader has 12 campers how much does she spend on the books
lutik1710 [3]

Answer:

$7.50 multiplied by 12 = $90.00

Step-by-step explanation:

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A system of linear equations includes the line that is created by the equation y = x+ 3, graphed below, and the line through the
frez [133]

Answer:

  (8, 11)

Step-by-step explanation:

The 2-point form of the equation of a line is useful for the one where only points are given.

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  y = (3 -1)/(4 -3)(x -3) +1

  y = 2(x -3) +1

We can equate this to the expression for y in the given equation.

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Using the given equation, we can find y:

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The solution to the system is (x, y) = (8, 11).

3 0
3 years ago
how is solving an equation with the variable on each side similar to solving a two-step equation? (I’ll give brainliest :) )
katrin2010 [14]

Answer:

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Step-by-step explanation:

3 0
4 years ago
A store sells candy at $.50, $1, $1.50, $2, and $3 per kilogram. You can see that the unit price of candies and the amount of ca
Alecsey [184]

Answer:

Constant of variation = 3

Step-by-step explanation:

Given that a store is selling different candies costing  $.50, $1, $1.50, $2, and $3 per kilogram.

As given

Amount available to buy candies = $ 3

Suppose

Unit price of candies = x

Number of candies bough = y

Constant of variation = k

As we know the unit price of candies and number of candies bought vary inversely. As the unit price would increase the the number of candies bought in available amount ($3) would decrease.

So our formula to calculate formula for constant of variation would be as shown below:

k= xy →(1

Case 1

if we take unit price x to be $0.5, then we can buy 6 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (0.5)(6) = 3

Case 2

if we take unit price x to be $1, then we can buy 3 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1)(3) = 3

Case 3

if we take unit price x to be $1.5, then we can buy 2 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1.5)(2) = 3

Case 4

if we take unit price x to be $2, then we can buy 1.5 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (2)(1.5) = 3

Case 4

if we take unit price x to be $3, then we can buy 1 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (3)(1) = 3

So, our constant of variation is 3.

4 0
4 years ago
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