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The length of a rectangle is 5 inches more than its vedth. The area of the rectangle is equal to

jarptica [38.1K]

Answer:

The width = x = 14

The length = x+5 = 14+5 = 19

Step-by-step explanation:

Let l = length, w = width, A = area = l×w , and P = perimeter = 2(l+w)

Let 'x' be the width

As the length 'l' of a rectangle is 5 inches more than its width.

so the length will be = x+5

As the Area of the rectangle is equal to 2 inches more than 4 times the perimeter.

A = 4P + 2

so the equation becomes

l × w = 4×2(l+w)+2

substituting w=x, l = x+5,

(x+5)x = 8(x+5+x)+2

x²+5x = 8(5+2x)+2

x²+5x = 40+16x+2

x²+5x = 16x+42

x²+5x-16x-42 =0

x²-11x-42=0

$x^2-11x=42$

$\mathrm{Add\:}a^2=\left(-\frac{11}{2}\right)^2\mathrm{\:to\:both\:sides}$

$x^2-11x+\left(-\frac{11}{2}\right)^2=42+\left(-\frac{11}{2}\right)^2$

$x^2-11x+\left(-\frac{11}{2}\right)^2=\frac{289}{4}$

$\left(x-\frac{11}{2}\right)^2=\frac{289}{4}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{11}{2}=\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{\sqrt{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{2}$

$x-\frac{11}{2}=\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=\frac{17}{2}+\frac{11}{2}$

$x=14$

similarly solving

$x-\frac{11}{2}=-\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=-\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=-\frac{17}{2}+\frac{11}{2}$

$x=-3$

so

x = 14, or x = -3

As the width 'x' can not be negative.

so x = 14

Thus,

The width = x = 14

The length = x+5 = 14+5 = 19

6 0

3 years ago

David made a class banner out of a large rectangular piece of paper. He cut a triangular piece out of one side. what is the area

VikaD [51]

The height would be the same as the rectangular piece of paper as well as the length so what you would do is you do heights times Lanks divide that by two and you would get the Square inches of the banner hope it helps

8 0

3 years ago

Question about a rational expression

sesenic [268]

-9=6/v

You have to multiply v both sides because
6/v x v = 6 and helps you get rid of the v on the right side.
If you multiply by 6, 6/v x 6 = 36/v, that’s why it don’t work.

Answer:
-9=6/v
-9v=6
v=-6/9
v=-2/3

3 0

2 years ago

Write an equation for a circle with center at (5,-2) and diameter of 8 centimeters.

mars1129 [50]

Answer:

$(x-5)^2+(y+2)^2=16$