1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mash [69]
2 years ago
6

The correlation between two variables is –0.63 for a sample of 20 observations. What is the coefficient of determination between

the two variables? 0.63 0.3969 0 .7937 We can’t determine it because sample size is smaller than 30.
Mathematics
1 answer:
erastovalidia [21]2 years ago
7 0

Answer:

b) 0.3969

Step-by-step explanation:

Given that the correlation between two variables is –0.63 for a sample of 20 observations.

Correlation is the measure of linear association between two variables.  Normally this varies from -1 to 1 . Here this is given as -0.63

Coefficient of determination has to be found out

Coefficient of determination, being the cause of variation caused by one variable on another is obtained by square correlation coefficient.

Hence coefficient of determination = r^2 = (-0.63)^2\\=0.3969

Hence correct option is option b) 0.3969

You might be interested in
Ayden wants to sell a total of $150 worth of candy bars for his school fundraiser. Each candy bar costs $1.50. How many candy ba
worty [1.4K]

Answer:

100 Candy Bars

Step-by-step explanation:

Hey!

==================================================================

Ayden wants to sell a total of $150 worth of candy bars for his school fundraiser. Each candy bar costs $1.50. How many candy bars will he have to sell in order to meet his goal?

--------------------------------------------------------------------------------------------------------------

We can create an algebraic Equation to solve this.

<u>- We know that Each Candy Bar costs $1.50.</u>

<u>-We multiply the Amount of Candy Bars with the price. </u>

<u>-We know the profit should be $150</u>

⇒ 1.50x = 150

-<u>Divide</u> by 1.50 on both sides

⇒ 1.50x/1.50 = 150/1.50

-<u>Simplify</u>

⇒ x = 100

==================================================================

<em>Hope I Helped, Feel free to ask any questions to clarify :) </em>

<em> Have a great day! </em>

<em> More Love, More Peace, Less Hate. </em>

<em>        -Aadi x</em>

4 0
3 years ago
Help pls ill gve brainlist &lt;3 or however you spell it
telo118 [61]

Answer:

1) Is 3 for K

2) is 4 for X

3) is 56 for Y

8 0
2 years ago
Read 2 more answers
The y intercept of the line 5y + 2x -3=0
Alecsey [184]

5y+2x-3=0

5y=-2x+3

y=-2/5 x+3

Sope intercept of the line is y=-2/5 x+ 3/5.

The intercept is 3/5.

Check: x=0 when y=3/5

5y+2x-3=0

5(3/5)+2x-3

3+2x-3=0

2x=0

x=0

Correct

The answer is 3/5.

5 0
2 years ago
Chris and Mikala each got a candy bar that were the same size. Chris cut his
bazaltina [42]

Answer:

Chris ate more of his candy bar

6 0
3 years ago
Solve. Use models to help you.
oksian1 [2.3K]

Answer:

3.38

Step-by-step explanation:

x + y + z = 16.9

x = 2y

y = z

y=y

2y (x) + y(y) + y(z) = 16.0

5y = 16.9

y = 3.38

4 0
2 years ago
Other questions:
  • Helppppppppppppppppp
    7·2 answers
  • Math question down below
    8·1 answer
  • A company paid $150,000, plus a 7% commission and $5,000 in closing costs for a property. The property included land appraised a
    11·1 answer
  • A local clothing shop is marking down all of its summer clothes by 75%. sarah would like to purchase a swimsuit that is original
    14·2 answers
  • Someone please help!! Determine the intercept of the line. ​
    12·2 answers
  • Which ordered pair is a solution of the equation?<br> - 4x + 7 = 2y - 3
    7·2 answers
  • Situation:
    5·1 answer
  • A number b minus 6.9 is less than or equal to 12 . Write this word sentence as an inequality.
    7·1 answer
  • I’m about to spam questions if you can answer them please do .
    6·2 answers
  • Can someone help please
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!