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3 years ago

Find the value of x to the nearest degree.

Mathematics

1 answer:

Vinvika [58]3 years ago

3 0

Answer: 77°

<u>Step-by-step explanation:</u>

In relation to ∠X, 3 is the adjacent side and 13 is the opposite side.

$tan\ \theta=\dfrac{opposite}{adjacent}\\\\tan\ x=\dfrac{13}{3}\\\\x = tan^{-1}\bigg(\dfrac{13}{3}\bigg)\\\\.\ =77$

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lawyer [7]

It is 5 you just have to count

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3 years ago

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°

Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = $c^{2}$ = $a^{2} + b^{2}$

a = 7 and b = 11

$a^{2}$ = 49

$b^{2}$ = 121

Plugging in the values, we will get:

$c^{2}$ = 49 + 121

$c^{2}$ = 170

c = $\sqrt{170}$

To calculate the unknown angle B, we can use law of sine.

Law of sine = $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

So,

$\frac{c}{sinC}$ = $\frac{b}{sinB}$

$\frac{\sqrt{170} }{sin90}$ = $\frac{11}{sinB}$

Sin90 = 1

sinB = $\frac{11}{\sqrt{170} }$

B = $sin^{-1}$ ( $\frac{11}{\sqrt{170} }$ )

B = 57.5°

8 0

3 years ago

Jasmine is part of a bowling league and wants to beat the team record of an average score of 240 out of 300 possible points per

hoa [83]

Answer:

her score in sixth game is 270

Step-by-step explanation:

The computation of the Jasmine score in her sixth game is shown below:

Let us assume her sixth game score is x

And, the first five games are 252, 227, 210, 239, 242

And, the average score is 240

So, the following formula should be used

(252 + 227 + 210 + 239 + 242 + x) ÷ 6 = 240

252 + 227 + 210 + 239 + 242 + x = 240 × 6

252 + 227 + 210 + 239 + 242 + x = 1,440

x = 270

Hence, her score in sixth game is 270

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3 years ago

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Lorico [155]

Answer:

x=-1/5

double zero

Step-by-step explanation:

(5x+1)(5x+1)

x=-1/5

double zero

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2 years ago

How many times larger is 1.9 × 10^-8 is than 4.2 × 10^-13<br><br>please help

Jet001 [13]

Answer:

hope this helps!

Step-by-step explanation:

You have to divide:

1.9x10^-8 ÷ (4.2x10^-13)

= appr .45 x 10^5

= .45 x 100000

= appr 45,000 times as large

source: https://www.jiskha.com/questions/1857280/estimate-how-many-times-larger-1-9x10-8-is-than-4-2x10-13

credit: mathhelper

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3 years ago