Answer:
Step-by-step explanation:
d(x)=√((x-2)2+(y-0)²)
=√((x-2)²+y²)
=√((x-2)²+(x-1)²)
=√(x²-4x+4+x²-2x+1)
=√(2x²-6x+5)
D=d²(x)=2x²-6x+5

This is just about similar triangle
mn=2jl=22
mo=2lk=26
jk=2on=40
Answer:
1,712,304 ways
Step-by-step explanation:
This problem bothers on combination
Since we are to select 5 subjects from a pool of 48 subjects, the number of ways this can be done is expressed as;
48C5 = 48!/(48-5)!5!
48C5 = 48!/43!5!
48C5 = 48×47×46×45×44×43!/43!5!
48C5 = 48×47×46×45×44/5!
48C5 = 205,476,480/120
48C5 = 1,712,304
Hence this can be done in 1,712,304ways
Answer:
The figure is attached and the total distance is 1031 feet.
Step-by-step explanation:
The graph is indicated in the attached figure.
For calculation of distance consider following
Point Flagpole is (0,0)
Point Clue1 is (0,5)
Point Clue2 is (6,0)
Point Clue3 is (0,-5)
So the distance is calculated as follows
Substituting the values
![d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\](https://tex.z-dn.net/?f=d_%7BT%7D%3D%5B%5Csqrt%7B%280-0%29%5E2%2B%285-0%29%5E2%7D%2B%5Csqrt%7B%286-0%29%5E2%2B%280-5%29%5E2%7D%2B%5Csqrt%7B%280-6%29%5E2%2B%28-5-0%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B%280%29%5E2%2B%285%29%5E2%7D%2B%5Csqrt%7B%286%29%5E2%2B%28-5%29%5E2%7D%2B%5Csqrt%7B%28-6%29%5E2%2B%28-5%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B0%2B25%7D%2B%5Csqrt%7B36%2B25%7D%2B%5Csqrt%7B36%2B25%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B25%7D%2B%5Csqrt%7B61%7D%2B%5Csqrt%7B61%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B5%2B7.81%2B7.81%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B20.62%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D1031%20%5Ctext%7B%20feet%7D%5C%5C)
So the total distance travelled is 1031 feet.