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3 years ago

Which statement is true?

Mathematics

2 answers:

ira [324]3 years ago

4 0

The range of h(x) is core

Oliga [24]3 years ago

4 0

Answer:

Step-by-step explanation:

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To solve one-step equations, we do the inverse (opposite) of whatever operation is being performed on the variable, so we get th

olganol [36]

Answer:

$y = 2$

Step-by-step explanation:

Given

$5 + y = 7$

Required

Solve

From the analysis attached to the question, we can solve this equation by subtracting 5 from both sides:

$5 + y = 7$

$-5 + 5 + y = 7 - 5$

$0 + y = 2$

$y = 2$

3 0

3 years ago

Please help me pls pls pls

bonufazy [111]

Solution:
Upper Quartile = 17
Lower Quartile = 14
Interquartile range = 17 - 14
= 3

4 0

3 years ago

Angie and Becky each completed a separate proof to show that the measures of vertical angles AKG and HKB are equal. Who complete

BigorU [14]

Linear pair angles, which are angles that together form a straight line are

supplementary angles.

The one that completed the proof incorrectly is <u>Becky</u>.

Reasons:

The two column proof is presented as follows;

Statement ${}$ Reason

1. Segment GH intersects segment AB at K ${}$ 1. Given

2. m∠AKG + m∠HKB = 180° ${}$ 2.Definition of Supplementary Angles

m∠GKB + m∠HKB = 180°

3. m∠AKG + m∠HKB = m∠GKB + m∠HKB ${}$ 3. Substitution property

4. m∠AKG = m∠HKB ${}$ 4. Subtraction Property

The difference between Angie's Proof and Becky's Proof is in Statement 2.

Angie states that; m∠AKG + m∠HKB = 180° and m∠GKB + m∠HKB = 180° by definition of Supplementary Angles

Becky states that; m∠AKG + m∠HKB = 180° and m∠GKB + m∠HKB = 180° by Angle Addition Postulate

Becky's proof is incorrect because the measure of angles m∠AKG and

m∠HKB and m∠GKB and m∠HKB are not given, therefore, the use of the

reason of Angle Addition Postulate in statement 2. is incorrect.

Learn more here:

brainly.com/question/13204208

8 0

3 years ago

Emily is entering a bicycle race for charity. Her mother pledges $0.10 for every 0.75 mile she bikes. If Emily

Mrrafil [7]

Answer:

1.60$

Step-by-step explanation:

first, we have to figure out haw many times 0.75 goes into 12

pretty sure you just want the answer to this and not me to explain the whole thing so:

if you multiply 0.75 by 16 you get 12.

16x0.10= 1.6

so her mother gave 1.60$

4 0

3 years ago

Exercise 12.1.2: The probability of an event under the uniform distribution - random permutations. About A class with n kids lin

Nataly [62]

Answer:

a) $P_a=\frac{1}{n}$

b) $P_b=\frac{1}{n(1-n)}$

c) $P_c=\frac{2}{n}$

Step-by-step explanation:

The question is incomplete:

<em>(a) What is the probability that Celia is first in line? (b) What is the probability that Celia is first in line and Felicity is last in line? (c) What is the probability that Celia and Felicity are next to each other in the line?</em>

a) The probability that Celia is first in line, if there are n kids and all of them have the same chance, is 1/n.

$P_a=\frac{1}{n}$

b) The probability that Celia is first in line and Felicity is last in line is

$P_b=\frac{1}{n} \frac{1}{n-1} =\frac{1}{n(1-n)}$ .

It is deducted like that:

If Celia is placed in the first line (what has a probablity of 1/n), there are left (n-1) kids. Then, the probability of placing Felicity in the last place is 1/(n-1).

Both probabilities multiplied give 1/(n*(n-1)).

c) The probability that Celia and Felicity are next to each other in the line is

$P_c=\frac{2(n-1)!}{n!}=\frac{2}{n}$

There are n! combinations for kids lines, where (n-1)! permutations have Celia before Felicity and other (n-1)! permutations have Felicity before Celia.

Then, we have 2(n-1)! permutations that have Celia and Felicity next to each other, over n! permutations possible.

5 0

3 years ago