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Irina-Kira [14]
3 years ago
8

Which statement is true?

Mathematics
2 answers:
ira [324]3 years ago
4 0
The range of h(x) is core
Oliga [24]3 years ago
4 0

Answer:

Step-by-step explanation:

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How many more vertices does a rectangular prism have, compared to triangular pyramid?
iVinArrow [24]
The answer is C it’s 5
4 0
3 years ago
Read 2 more answers
Solve for m: -13 =5(1+4m)-2m
erastovalidia [21]

Answer:


Step-by-step explanation:


-13 = 5(1+4m)-2m

-13=5+20m-2m

-13=5+18m

-13-5=18m

(-13-5)/18=m


6 0
3 years ago
What is the question?
max2010maxim [7]

Answer:

(23, 4)

Step-by-step explanation:

If we use substitution, we need to rewrite the 2nd equation so we can substitute it into the first.

Step 1: Rewrite 2nd equation

x = 5y + 3

Step 2: Substitution

2(5y + 3) - 5y = 26

Step 3: Distribute

10y + 6 - 5y = 26

Step 4: Combine like terms

5y + 6 = 26

Step 5: Isolate <em>y</em>

5y = 20

y = 4

Step 6: Find <em>x</em>

x - 5(4) = 3

x - 20 = 3

x = 23

And we have our final answer!

7 0
3 years ago
Read 2 more answers
A lake contains 4 distinct types of fish. Suppose that each fish caught is equally likely to be any one of these types. Let Y de
gregori [183]

a= μ-3.16*σ , b= μ+3.16*σ if each fish caught is equally likely to be any one of these 4 distinct types.

<h3>What is meant by Chebyshev inequality?</h3>

Chebyshev's inequality is a probability theory that ensures that, over a vast range of probability distributions, no more than a particular proportion of values would be present within a selected limits or range as from mean. In other words, only a certain fish caught will be discovered within a given range of the distribution's mean.

The formula for which no more than a particular number of values can exceed is 1/K2; in other words, 1/K2 of a distribution's values can be more than or equal to K standard deviations away from the distribution's mean. Furthermore, it asserts that 1-(1/K2) of a distribution's values must be within, but not include, K standard deviations of the distribution's mean.

How to solve?

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y =  the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 →  1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

P{Y≥b} ≥ 0.90  →  1- σ²/(σ²+λ²)=  1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ

then for

P(Y≥ μ+3*σ ) ≥ 0.90

In order to learn more about Chebyshev inequality, visit:

brainly.com/question/24971067

#SPJ4

4 0
1 year ago
DETERMINE WHETHER THE EXPRESSIONS BELOW ARE CORRECT OR NOT AND DO THE CORRECTION
Assoli18 [71]

Answer:

First ans is true but second one is not the cotrect

one

4 0
3 years ago
Read 2 more answers
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