Question

Given ^2 -6x+8 and g(x) =x-2" alt="f(x) =x^2 -6x+8 and g(x) =x-2" align="absmiddle" class="latex-formula">, solve f(x) -g(x) using a table of values

Answer 1

For this case we have the following functions:

$f (x) = x ^ 2-6x + 8\\g (x) = x-2$

We must subtract the functions:

$f (x) -g (x) = x ^ 2-6x + 8- (x-2)\\f (x) -g (x) = x ^ 2-6x + 8-x + 2\\f (x) -g (x) = x ^ 2-7x + 10$

We build a table of values for $x = 0,1,2,3.$

$x = 0, f (x) -g (x) = 0 ^ 2-7 (0) + 10 = 10\\x = 1, f (x) -g (x) = 1 ^ 2-7 (1) + 10 = 1-7 + 10 = 4\\x = 2, f (x) -g (x) = 2 ^ 2-7 (2) + 10 = 4-14 + 10 = 0\\x = 3, f (x) -g (x) = 3 ^ 2-7 (3) + 10 = 9-21 + 10 = -2$

Answer:

$f (x) -g (x) = x ^ 2-7x + 10$