215 because you would add and subtract the numbers as you go them you come out with your answer
Answer:
10 ball caps
Step-by-step explanation:
In this question, we are trying to know the number of caps the manger would buy that would equate the cost at both companies.
How do we get this?
Since we do not know the number of caps, let’s assign a variable. Let the number of caps that is required be x. Let’s now make some costings in terms of x. We proceed;
Company X charges $50 fee plus $7 per cap. Total amount company X will charge on x caps will be; $50 + $7(x) = $50 + $7x
Company Y will charge $30 plus $9 per cap. Total amount company Y will charge on x caps will be $30 + $9(x) = $30 + $9x
We are trying to look at the value of x that will make both costs equal. What we do is to equate both costs.
30 + 9x = 50 + 7x
We simply by taking like terms to the same sides
9x-7x = 50-30
2x = 20
x = 20/2 = 10
X = 10
So what this means is that manger has to buy 10 caps to have the same cost in both companies
Answer:
65625/4(x^5)(y²)
Step-by-step explanation:
Using binomial expansion
Formula: (n k) (a^k)(b ^(n-k))
Where (n k) represents n combination of k (nCk)
From the question k = 5 (i.e. 5th term)
n = 7 (power of expression)
a = 5x
b = -y/2
....................
Solving nCk
n = 7
k = 5
nCk = 7C5
= 7!/(5!2!) ------ Expand Expression
=7 * 6 * 5! /(5! * 2*1)
= 7*6/2
= 21 ------
.........................
Solving (a^k) (b^(n-k))
a = 5x
b = -y/2
k = 5
n = 7
Substituting these values in the expression
(5x)^5 * (-y/2)^(7-5)
= (3125x^5) * (-y/2)²
= 3125x^5 * y²/4
= (3125x^5)(y²)/4
------------------------------------
Multiplying the two expression above
21 * (3125x^5)(y²)/4
= 65625/4(x^5)(y²)
The answer will be 21u^6v^8
