To calculate the relative vector of B we have to:
![P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]](https://tex.z-dn.net/?f=P_B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C3%5C%5C-2%5C%5C3%2F2%5Cend%7Barray%7D%5Cright%5D)
The coordenates of:
, with respect to B satisfy:

Equating coefficients of like powers of t produces the system of equation:

After solving this system, we have to:

And the result is:
![P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]](https://tex.z-dn.net/?f=P_B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C3%5C%5C-2%5C%5C3%2F2%5Cend%7Barray%7D%5Cright%5D)
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Answer:
c im pretty sure
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
The function is 4x.
For every pound you have, you will have 4 times that amount in total cost. This is because of the pattern being shown. Example: 3 × 4 = 12 6 × 4 = 24 9 × 4 = 36.. and it just goes on and on.
You'd use the equation a^2 + b^2 = c^2 (**** ^2 means squared****)
a = 60
b = 11
c = ?
60^2 + 11^2 = c^2
3600 + 121 = c^2
3721 = c^2
then just square root 3721 and c^2
c = 61 feet
Answer:
18 hours
Step-by-step explanation:
Let the volume of the pool be x. Since pipe A filled the pool in 6 hours, the rate of pipe A = x / 6.
Let the rate of pipe b be y, Hose A filled the pool alone for the first 2 hours, this means that the volume filled in the 2 hours is x/6(2 hours) and the two hoses, working together, then finished filling the pool in another 3 hours for the 3 hours the volume filled is x/6(3) + y(3). hence the total time is:
x/6(2) + x/6(3) + y(3) = x
x/3 + x/2 + 3y = x
Multiply through by 6:
2x + 3x + 18y = 6x
5x + 18y = 6x
18y = x
y = x/18
The rate of pipe B is x/18, this means it would take pipe B 18 hours to full the pool alone