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2 years ago

There are 72 students in the gym. 45 students are girls. The rest are boys. What is the ratio of boys to girls?

Mathematics

1 answer:

PIT_PIT [208]2 years ago

3 0

Answer:

3 to 5

Step-by-step explanation:

To find the number of boys, take the total students and subtract the girls

72 -45 =27

We want the ratio of boys:girls

boys:girls

27:45

Divide each number by 9

27/9:45/9

3 : 5

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198/43

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3 years ago

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2 years ago

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What is the reciprocal of 6/5? <br> A. 1 <br> B. 1 1/5 <br> C. 12/10 <br> D. 5/6

Sergio039 [100]

The reciprocal of 6/5 is D. 5/6

Reciprocal simply means swapping the position of the numbers in the fraction. The numerator becomes the denominator and the denominator becomes the numerator.

We need to get reciprocal of a fraction when division is performed.

For example: 2 ÷ 1/5

2 may be a whole number but in fraction form it is 2/1.

1st fraction = 2/1
2nd fraction = 1/5

In dividing fractions, the 1st step we need to do is to get the reciprocal of the 2nd fraction.

1/5 ⇒ 5/1

Then, we multiply the 1st fraction to the reciprocal of the 2nd fraction.
2/1 * 5/1 = 10

So, 2 ÷ 1/5 = 10

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3 years ago

Read 2 more answers

How to simplify 8x+5x

uranmaximum [27]

Answer: 13x

Step-by-step explanation: Since 8x and 5x are like terms, we can add them together.

8x+5x=13x

Have a nice day! :)

3 0

2 years ago

A three inch diameter pulley on an electric motor that runs at 1800

Bezzdna [24]

Answer:

a) 3 inch pulley: 11,309.7 radians/min

6) 6 inch pulley: 5654.7 radians/min

b) 900 RPM (revolutions per minute)

Step-by-step explanation:

Hi!

When a pulley wirh radius R rotantes an angle θ, the arc length travelled by a point on its rim is Rθ. Then the tangential speed V is related to angular speed ω as:

$V=R\omega$

When you connect two pulleys with a belt, if the belt doesn't slip, each point of the belt has the same speed as each point in the rim of both pulleys: Then, both pulleys have the same tangential speed:

$\omega_1 R_1 = \omega_2 R_2\\$

$\omega_2 = \omega_1 \frac{R_1}{R_2} =1800RPM* \frac{3}{6}= 900RPM$

We need to convert RPM to radias per minute. One revolution is 2π radians, then:

$\omega_1 = 1800*2\pi \frac{radians}{min} = 11,309.7\frac{radians}{min}$

$\omega_2 = 5654.7 \frac{radians}{min}$

The saw rotates with the same angular speed as the 6 inch pulley: 900RPM

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3 years ago