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2 years ago

13

Jamal works as an electrician apprentice he rewired for electrical outlets for electrical outlets in 1 1/2 hours. If it worked a

t the same pace for 7.5 hours, how many outlets will he rewire?
5 outlets
13 outlets
20 outlets
30 outlets

1 answer:

Nata [24]2 years ago

6 0

Answer:

13

Step-by-step explanation:

they go at diffrent speed of electric.

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For each mile that Jason runs, Meagan runs 1/4 Mile farther. If Jason ran 6 miles,how far did Megan run ?

Darina [25.2K]

6/1 × 1/4 = 6/4
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Meagan ran 7 1/2 miles.

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3 years ago

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Answer:

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3 years ago

Pls help sixowiskosixo

erma4kov [3.2K]

The given question is a quadratic equation and we can use several methods to get the solutions to this question. The solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

<h3>Quadratic Equation</h3>

Quadratic equation are polynomials with a second degree as it's highest power.

An example of a quadratic equation is

$y = ax^2 + bx + c$

The given quadratic equation is $24x^2 + 2x = 15$

Let's rearrange the equation

$24x^2 + 2x = 15\\24x^2 + 2x - 15 = 0$

This implies that

a = 24
b = 2
c = -15

The equation or formula of quadratic formula is given as

$y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}$

We can substitute the values into the equation and solve

$y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}\\y = \frac{-2 +- \sqrt{2^2 -4 * 24 * (-15)} }{2*24} \\y = \frac{-2+-\sqrt{4+1440} }{48} \\y = \frac{-2+-\sqrt{1444} }{48} \\y = \frac{-2+- 38}{48} \\y = \frac{-2+38}{48} \\y = \frac{3}{4}\\ \\or\\y = \frac{-2-38}{48} \\y = \frac{-40}{48} \\y = -\frac{5}{6}$

From the calculations above, the solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

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1 year ago

Rewrite the equation 4x - 5y = 20 into slope-intercept form and graph it.

natta225 [31]

Y= 4 - 4/5x all you have to do is make it go up 4 from 0 and either go down 4 and go right 5 or up 4 and to the left 5... hope this helped!

6 0

3 years ago

Suppose you drive a car 392 mi on a tank of gas. The tank holds 14 gallons. The number of miles traveled vaties directly with th

Serhud [2]

Preliminary Problem

Givens

Miles = m = 392 miles

Gallons = G = 14 gallons

Miles per gallon = mpg

Formula

miles = miles per gallon * number of gallons.

Solve

392 = mpg * 14 Divide by 14

392 / 14 = mpg

28 = mpg which is really quite good. Our vehicle gets 44 mpg but it's a 4 cylinder. It's meant to get that kind of milage.

Part A

Let x = the number of gallons used

Let y = the number of miles driven

y = k*x

Part B

y = k* x

k =28 mpg

11700 = 28*x

11700 /28 = x

x = 417.86

If this is incorrect please put some more facts in. The question does not seem complete.

7 0

3 years ago