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DedPeter [7]
4 years ago
12

Find the simplified product (Sqrt 2x^3)(sqrt 18x^5)

Mathematics
2 answers:
Vikki [24]4 years ago
7 0

Answer:

6x^4

Step-by-step explanation:

the expression we have is:

(\sqrt{2x^3})( \sqrt{18x^5} )

Because it is a product of two square roots, we can put it together in one:

\sqrt{(2x^3)(18x^5)}

and we carry out the multiplication inside the square root

(to multiply the variable x we sum the exponents 3+5=8)

\sqrt{2*18x^{3+5}}\\\\=\sqrt{36x^8}  \\

and now we can take the square root of 36 which is 6.

and to take the square root if x^8 we divide the exponent by 2:

=6x^{8/2}\\=6x^4

the simplified product is:  6x^4

fiasKO [112]4 years ago
4 0

The answer is 6x^4

You can find the equation to your question here

brainly.com/question/9720288#readmore

The answer explains in detail and is easy to understand.

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Now given a rope hanging from the top of a pole. The end lying on the ground is 3 chi long. When tightly stretchedit is 8 chi fr
drek231 [11]

Answer:

Height of the pole = 9.17 chi.

Length of the rope = 12.17 chi.

Step-by-step explanation:

Given that the rope is hanging from the top of a pole having height x chi and the portion of the rope lying on the ground is 3 chi.

So, the length of the rope= x + 3 chi.

Let AB represents the pole in the figure, and one end of the rope is at point A.

When the rope is tightly stretched, let C be the other end of the rope as shown in the triangle.

The length of the rope = AC.

\Rightarrow AC=x+3 chi.

Distance from the bottom of the pole, point A, to the other end of the pole, point B, is 8 chi.

So, BC=8 chi.

As the triangle ABC is a right-angled triangle, so by using Pythagoras theorem,

AC^2= AB^2+BC^2

\Rightarrow (x+3)^2=x^2+8^2

\Rightarrow x^2+6x+9=x^2+64

\Rightarrow 6x=64-9=55

\Rightarrow x=55/6=9.17 chi.

Hence, the height of the pole, AB=x=9.17 chi,

and the length of the rope, x+3=9.17+3=12.17 chi.

8 0
3 years ago
Please help im in a rush
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Step-by-step explanation:

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Count the number of 0

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