Answer:
If f(x) = 9–4 |+1|, find f(-5)?
Step-by-step explanation:
15
-7
7
23
ANSWER 23
√<span>108x^5y^6
First, break up </span><span>√108 :
</span>√108 = √4 x √27 = 2 x √3 x √9 = 2 x √3 x 3 = 6<span>√3
</span><span>Since the x^5 is under a root of 2, that means we can take out an x^2 and leave one x under the radical :
</span>√x^5 = x^2 (<span>√x)
</span><span>Since the y^6 is raised to an even power and the root is even (2), that means we can take out all of the y's without leaving any under the radical :
</span><span>√y^6 = y^3
</span><span>Now, combine all of our simplified forms into one expression:
6x^2y^3</span><span>√3x</span><span>
</span>
Answer:
x=1
y=8.6
Explanation:
first start by assigning a random value to a random variable, let’s say x=1
from there the equation becomes solveable
9x1+-5y=-34
simplify
9-5y=-34
-9 from both sides
-5y=-43
divide both sides by-5
y=8.6
hope this helps :)
Okay!
Notable things in the problem:
2011 <u>minutes</u> <u>AFTER</u> the beginning of January 1rst.
12:00AM will be our starting time, because that's when January 1rst begins.
It'll be a bit easier to work with if we convert the 2011 minutes into hours.
So take 2011 minutes and divide it by 60 to get the number of hours.
2011 / 60 = 33 hours and 31 minutes
You wouldn't be able to easily get the exact number of minutes from a calculator. You'll need to use long division. The remainder will be the number of minutes. If you want to check you can multiply the number of hours by 60 and add 31 to the product. If it doesn't equal 2011 minutes then something is amiss.
12:00 AM
Since we know this is a 24 hour clock we can subtract 24 from our number of hours. (Just remember that this is the next day)
12:00 AM with 9 hours and 31 minutes left.
9:31 AM a day later is our time!<u />
On the right hand side it should be m(x-x1)
Y-4=-3(x-5)
Y=-3x+19
