The diagram shows a right triangle with legs that measure 4 and 7.

Mathematics

1 answer:

anyanavicka [17]3 years ago

3 0

Calculate the hypotenuse( h ) using Pythagoras' identity

h =√(4² + 7²) = √(16 + 49) = √65

sinΘ = 4 / √65 ⇒ cscθ = √65 / 4

cosθ = 7/ √65 ⇒ secθ = √65 / 7

tanθ = $\frac{4}{7}$ ⇒ cotθ = $\frac{7}{4}$

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