Question

The diagram shows a right triangle with legs that measure 4 and 7.

Answer 1

Calculate the hypotenuse( h ) using Pythagoras' identity

h =√(4² + 7²) = √(16 + 49) = √65

sinΘ = 4 / √65  ⇒ cscθ = √65 / 4

cosθ = 7/ √65 ⇒ secθ = √65 / 7

tanθ = $\frac{4}{7}$ ⇒ cotθ = $\frac{7}{4}$