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MA_775_DIABLO [31]
3 years ago
9

What is 3k-1=7k+2 please help me find the answer

Mathematics
2 answers:
dybincka [34]3 years ago
8 0
3k-1=7k+2
    +1      +1
 3k=7k+3
-7k  -7k
-4k=3
divide each side by -4
/-4    /-4

k=-3/4
or
k=-.75

Arada [10]3 years ago
8 0
Let's solve your equation step-by-step.
3
k
1
7
k
2
Step 1: Subtract 7k from both sides.
3
k
1
7
k
7
k
2
7
k
4
k
1
2
Step 2: Add 1 to both sides.
4
k
1
1
2
1
4
k
3
Step 3: Divide both sides by -4.
4
k
4
3
4
k
3
4
Answer:
k
3
4

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borishaifa [10]

Answer:

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Step-by-step explanation:

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t(1)=3.5+2

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4 0
3 years ago
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Answer:

\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }

Step-by-step explanation:

Hello, please find below my work.

2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0

\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}

Hope this helps.

Do not hesitate if you need further explanation.

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4 0
3 years ago
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Dima020 [189]

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Step-by-step explanation:

Given

b = 22^{\circ}

Whole\ Angle = 300^{\circ}

Required

Find the measure of a

Since there is no diagram to support the question, we'll assume that:

a + b = Whole\ Angle

This gives:

a + 22^{\circ} = 300^{\circ}

Subtract 22 from both sides

a + 22^{\circ}-22^{\circ} = 300^{\circ}-22^{\circ}

a  = 300^{\circ}-22^{\circ}

a  = 278^{\circ}

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Hopefully this helps <em>you !</em>

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