You need to use this formula:
([a]/[sinA])=([c]/[sinC])-I am going to use 'a' for the x, and 'c' for 16(square root of 3)
Now its just getting 'a' by itself.
([c] times [sinA])/([sinC])=[a]
[c]=16 square root of 3
sinA=sin(60)=(square root of 3)/2
sinC=sin(90)=1
Plug it in to get 24 for a, or x. Do the same to figure out y with the new sides.
The final y is:
8 square root of 3
Final answer is C.
Answer:
1st option
Step-by-step explanation:
To find the difference of the given matrices, we just need to subtract the corresponding elements of the two matrices as shown below:
![\left[\begin{array}{cc}-4&8\\3&12\end{array}\right] -\left[\begin{array}{cc}2&1\\-14&15\end{array}\right] \\\\ \\ =\left[\begin{array}{cc}-4-2&8-1\\3-(-14)&12-15\end{array}\right]\\\\ \\ =\left[\begin{array}{cc}-6&7\\17&-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4%268%5C%5C3%2612%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%261%5C%5C-14%2615%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%20%5C%5C%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4-2%268-1%5C%5C3-%28-14%29%2612-15%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%20%5C%5C%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-6%267%5C%5C17%26-3%5Cend%7Barray%7D%5Cright%5D)
Thus, 1st option gives the correct answer
Step-by-step explanation:
<h2>
<em>y = ± 5⁄2 x</em></h2><h2>
<em>y = ± 5⁄2 xThe equation is the left half of the hyperbola. The domain is ( – ∞, – 1⁄5 ]. The range is ( – ∞, ∞ ). The vertical line test indicates that this is not the graph of a function.</em></h2>
An equality of two rations is called a porportion
Answer:
(4×x) 7> 80 :)
Step-by-step explanation:
