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Reptile [31]
3 years ago
13

A store holiday sale has an item marked down by $10 with an additional discount of 25% off the

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
5 0

Answer:

C : $58.36

Step-by-step explanation:

Given:

A store holiday sale has an item marked down by $10.

Discount on new price = 25%

Final price was $36.27.

Question asked:

what was the original ?

Solution:

Let original price = x

New price = x - 10

Original price - marked down amount - discount amount = $36.27

x - 10 -25\% of(x - 10 ) = 36.27\\

x - 10 - \frac{25}{100} (x - 10) = 36.27\\x - 10 - 0.25(x - 10) = 36.27\\x - 10 -0.25x +2.5 = 36.27\\0.75x - 7.5 = 36.27\\

Adding both side by 7.5

0.75x = 43.77\\

Dividing both side by 0.75

x = 58.36

Therefore, the original price was $58.36

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Your customer is located 100 miles from your office.
OlgaM077 [116]

Answer:

8:02 AM

Step-by-step explanation:

Find out how many minutes it takes to travel one mile:

60 divided by 45= 1.333334 minutes

It takes 1.333334 minutes to travel 1 mile, how long will it take to travel 100 miles:

1.333 times 100 = 133.3334

133.3334 rounds to 133 minutes

Add 15 minutes because you want to arrive early

133+15=148

Divide it by 60

148 divided by 60 = 2.466667

or do

148-120 (2 hours) = 28 minutes

It will take 2 hours and 28 minutes to get there

10:30-2:28= 8:02

4 0
3 years ago
Can someone please help me with this problem? You need to find the value of x and y by using the strategy of ELIMINATION. Please
Setler [38]

Answer:

x = 136/35; y = -⁹/₁₀

Step-by-step explanation:

(1)         7x + 8y = 20

(2)        7x – 2y = 29       Subtract (2) from (1)

                  10y =  -9        Divide each side by 10

(3)                 y =  -⁹/₁₀     Substitute (3) into (1)

      7x - 2(-⁹/₁₀) = 29

      7x + 18/10  = 29                       Subtract 18/10 from each side

      7x              =      29 - 18/10

      7x              = (290 - 18)/10

      7x              =          272/10        Divide each side by 7

        x              =           272/70

        x              =           136/35

x = 136/35; y = -⁹/₁₀

Check:

(1) 7(136/35) + 8(-⁹/₁₀) = 20

      136/5    -   72/10 = 20

      136/5    -   36/5  = 20

                      100/5  = 20

                       20      = 20

(2) 7(136/35) – 2(-⁹/₁₀)  = 29

       136/5    +    18/10 = 29

       136/5    +      ⁹/₅    = 29

                        145/5  = 29

                        29       = 29

5 0
3 years ago
What is1\7 the speed of a cheetah?
klio [65]
1/7 the speed of a cheetah is 10 mph because an average cheetah can run 70 miles per hour. This means time to do some division. Envision  the denominator of 1/7 (7) as 70 and then the numerator (1) should be 10. Divide 70 by 7 should be 10. Hope this helps.
4 0
3 years ago
Read 2 more answers
Suppose that the lifetime of tv tubes are normally distributed with a standard deviation of 1.1 years. Suppose that exactly 20%
IrinaK [193]

Answer:

4.924 years

Step-by-step explanation:

Lets denote X the lifetime of a tv tube (In years). X has distribution N(\mu, 1.1) , with \mu unknown.

We know that P(X < 4) = 0.2. Using this data, we can find the value of \mu throught standarization.

Lets call Z = \frac{X - \mu}{1.1} the standarization of X. Z has distribution N(0,1), and its cummulative function, \phi is tabulated. The values of \phi can be found in the attached file.

P(X < 4) = P(\frac{X - \mu}{1.1} < \frac{4 - \mu}{1.1}) = P(Z < \frac{4 - \mu}{1.1}) = \phi(\frac{4 - \mu}{1.1}) = 0.2

The value q such that \phi (q) = 0.2 doesnt appear on the table. We can find it by using the symmetry of the normal density function. The opposite of q, -q must verify that \phi(-q) = 0.8 , hence -q must be equal to 0.84. Thus, q = -0.84

But this value of q should match with the number \frac{4 - \mu}{1.1} , so we have

\frac{4- \mu}{1.1} = -0.84

4 - \mu = 1.1 * (-0.84) = -0.924

\mu = 4 - (-0.924) = 4.924

Thus, the expected lifetime of TV tubes is 4.924 years.

I hope this works for you!

Download pdf
7 0
4 years ago
#11 - In the diagram of triangle PST, QR is parallel to ST with PQ = 10 and
Goshia [24]

Answer:

<h2>The length of RT is 3.6 units.</h2>

Step-by-step explanation:

In the image attached, you can observe a representation of the problem.

Notice that we have two parallel lines with two transversal. That means we can use the proportionality theorem to create the following expression

\frac{PQ}{QS} =\frac{PR}{RT}

Where PQ=10, QS=4 and PR=9.

Replacing all values, and solving for the unknown quantity, we have

\frac{10}{4}=\frac{9}{x}  \\10x=36\\x=\frac{36}{10}\\ x=3.6

\therefore RT=3.6

Therefore, the length of RT is 3.6 units.

4 0
3 years ago
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