3 years ago

Help me with this please

Mathematics

1 answer:

marta [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Melania: 2 1/5 = 11/5

Cathy 1 3/4 as far as Melania did => 7/4 x 11/ 5 = 77 / 20 = 3 17/20

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What is 14c12?<br> A. 78<br> B. 91<br> C. 105<br> D. 120

Delicious77 [7]

9514 1404 393

Answer:

B. 91

Step-by-step explanation:

14C12 = 14!/(12!(14-12)!) = 14·13/(2·1) = 7·13 = 91

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3 years ago

17.2=h+4 what does h equal

weqwewe [10]

Subtract 4 from both sides and then your answer should be 13.2=h

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3 years ago

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what is the y-intercept of the equation of the line that is perpendicular to the line y = 3/5x 10 and passes through the point (

bazaltina [42]

Perpendiculare means the slopes multiply to -1

y=3/5x+10
slope is 3/5
3/5 times what is -1
-5/3 is answer

slope of perpenduclar is-5/3 find y int
y=-5/3+b
point given is (15,-5)
x=15
y=-5

-5=-5/3(15)+b
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the yintercept is y=20 or the oint (0,20)

6 0

3 years ago

Help get all this points pls

balandron [24]

It would be b.) y=5x+5

8 0

3 years ago

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Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary.

Rama09 [41]

Check the picture below.

now, we have a triangle with all three sides, thus we can use Heron's Area Formula on the triangle.

$\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=10\\ b=26.695\\ c=22\\ s=29.3475 \end{cases} \\\\\\ A=\sqrt{29.3475(29.3475-10)(29.3475-26.695)(29.3475-22)} \\\\\\ A=\sqrt{29.3475(19.3475)(2.6525)(7.3475)}\implies A\approx \sqrt{11066.007} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill A\approx 105.195~\hfill$

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3 years ago