A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Holy god gud luck on escaping that (*´ー｀*)
Answer: One vase should be placed 3 feet from the end of the mantel and the other vase should be placed 9 feet from the same end.
Step-by-step explanation:
You know that lenght of the mantel above their fireplace is 12 feet.
They want to place one vase 
of the distance from one end of the mantel. This distance in feet is:
They want to place the other vase 
of the distance from the same end of the mantel. Therefore, this distance in feet is:
Therefore, one vase should be placed 3 feet from the end of the mantel and the other vase should be placed 9 feet from the same end.
The answer is A
1/4, 1/4, 1/4, 1,4...
