The helicopter took off from the angle of 11°.
Molly is converting 2 yards to millimeters. will the number of millimeters be fewer than or greater than 2?
2 answers:
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The correct answer is C) t₁ = 375, 
.
From the general form,
, we must work backward to find t₁.
The general form is derived from the explicit form, which is
. We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us
Using the products of exponents, we can "split up" the exponent:
We know that 5⁻¹ = 1/5, so this gives us
Comparing this to our general form, we see that
Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375
The recursive formula for a geometric sequence is given by
, while we must state what t₁ is; this gives us
From the general form,
The general form is derived from the explicit form, which is
Using the products of exponents, we can "split up" the exponent:
We know that 5⁻¹ = 1/5, so this gives us
Comparing this to our general form, we see that
Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375
The recursive formula for a geometric sequence is given by
x=2
sorry for the bad handwriting btw.
Answer:
a) 0.125
b) 7
c) 0.875 hr
d) 1 hr
e) 0.875
Step-by-step explanation:l
Given:
Arrival rate, λ = 7
Service rate, μ = 8
a) probability that no requests for assistance are in the system (system is idle).
Let's first find p.
a) ρ = λ/μ
Probability that the system is idle =
1 - p
= 1 - 0.875
=0.125
probability that no requests for assistance are in the system is 0.125
b) average number of requests that will be waiting for service will be given as:
λ/(μ - λ)
= 7
(c) Average time in minutes before service
= λ/[μ(μ - λ)]
= 0.875 hour
(d) average time at the reference desk in minutes.
Average time in the system js given as: 1/(μ - λ)
= 1 hour
(e) Probability that a new arrival has to wait for service will be:
λ/μ =
= 0.875