The distance from Tressa's home to school is 
times the distance from Anton's home to school
From the question,
Tressa's home is 4/5 mile from school
and Anton's home is 3/5 mile from school.
To determine how many times the distance from Anton's home to school is the distance from Tressa's home to school, we will divide the distance from Tressa's home to school by the distance from Anton's home to school
That is, 4/5 mile ÷ 3/5 mile
∴ we get
Hence, the distance from Tressa's home to school is times the distance from Anton's home to school
Learn more here: brainly.com/question/17420260
X = 23/2
pls give brainliest if you found my answer helpful
Answer:
- (x -3)(x+3)(2x +1)
- (x -1)(x +1)(x +3)
- (2x -1)(2x +1)(x -4)
Step-by-step explanation:
A) 2x³ +x² -18x -9 = x²(2x +1) -9(2x +1) = (x² -9)(2x +1) = (x -3)(x+3)(2x +1)
__
B) x³ +3x² -x -3 = x²(x +3) -1(x +3) = (x² -1)(x +3) = (x -1)(x +1)(x +3)
__
C) 4x³ -16x² -x +4 = 4x²(x -4) -1(x -4) = (4x² -1)(x -4) = (2x -1)(2x +1)(x -4)
_____
In each case, the third-level factoring mentioned in step 4 is the factoring of the difference of squares: a² -b² = (a -b)(a +b).
_____
The step-by-step is exactly what you need to do. It is simply a matter of following those instructions. You do have to be able to recognize the common factors of a pair of terms. That will be the GCF of the numbers and the least powers of the common variables.
Circumference = r * 2 * pi
Circumference of track 1 is 376.8
