Car B and E are speeding up, while car C is slowing down.
Step-by-step explanation:
Acceleration (a) is the rate of change of velocity with time.It is calculated by dividing the change in velocity (Δv) with the time taken for the change to occur.In this question , the time is 10 sec in all cases.You divide the velocity in km/h by 3.6 to convert to m/s
In Car A
Δv=8.33-8.33=0m/s
t=10s
a=0 m/s² ⇒car is moving with same speed and in the same direction
Car B
Δv=5.55-0=5.55
t=10
a=5.55/10 =0.555 m/s² ⇒car is speeding up
Car C
Δv = 0-8.33= -8.33 m/s
t= 10
a= -8.33/10 = -0.833 m/s² ⇒car is slowing down
Car D
Δv= 0-0 =0
t=10s
a=0/10 =0 m/s² ⇒car is at rest
Car E
Δv = 8.33-5.55=2.78
t=10
a=2.78/10 = 0.278 m/s²⇒car is speeding up
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To find acceleration : brainly.com/question/13154163
Keyword : velocity
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