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3 years ago

Label each table as linearor non-linear.

1 answer:

5 0

NL = non-linear
L = linear

A) NL
B) NL
C) NL
D) NL

the fact that they are all non linear is weird but I think its right

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Given A DEF with D(5,-2), E(-3, 4), and F(-5, -6). Find the image points after: A reflection over the y axis, then a translation

dangina [55]

Answer:

D'' (-4,-6)

E'' (4,0)

F'' (6,-10)

Step-by-step explanation:

When the object is reflected over the y axis, the coordinates (x,y) changes to (-x,y)

so for D (5,-2) -------- D'(-5,-2)

E (-3,4) -------- E' (3,4)

F (-5,-6) ------- F'(5,-6)

The image D'E'F' is then translated using (x,y) ------ (x+1 , y-4)

D'(-5,-2) ------ (-5+1,-2-4) ------- D'' (-4,-6)

E' (3,4 ) --------( 3+1 , 4-4) ------- E'' (4,0)

F'(5,-6) --------- ( 5+1, -6-4) ------ F'' (6,-10)

The image points are ;

D'' (-4,-6)

E'' (4,0)

F'' (6,-10)

8 0

3 years ago

Can anyone help me with this and can you also explain how you got that answer please

Firlakuza [10]

Answer:

7.2

Step-by-step explanation:

Use the distance formula:

d = $\sqrt{(x2-x1)^2+(y2-y1)^2}$

Points of the diagonal: (-2, -2) and (2, 4)

d = $\sqrt{(2-(-2))^2+(4-(-2))^2}$

d = $\sqrt{(2+2)^2+(4+2)^2}$

d = $\sqrt{(4)^2+(6)^2}$

d = $\sqrt{16 + 36}$

d = $\sqrt{52}$

d ≈ 7.2

4 0

3 years ago

Solve f=(sqrtg/l)/2pi for l

jenyasd209 [6]

$f=\dfrac{\sqrt\dfrac{g}{l}}{2\pi}\\ 2\pi f=\sqrt{\dfrac{g}{l}}\\ \dfrac{g}{l}=4\pi ^2 f^2\\ l=\dfrac{g}{4\pi^2 f^2}\\$

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4 years ago

Find the product of 0.032 and -1.9

vesna_86 [32]

Answer:

i think it's -0.0608

Step-by-step explanation:

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3 years ago

Casey bought 7 packages of cupcakes with three cupcakes in each package . Jessica bought 45 chocolate cupcakes and 23 vanilla cu

postnew [5]

Jessica bought 47 more cupcakes than Casey.

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3 years ago

Read 2 more answers