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3 years ago

What is the decimal equivalent of 5 over 9? 0.5 bar 0.6 bar 0.8 bar 0.9 bar

Mathematics

2 answers:

igomit [66]3 years ago

5 0

Answer:

0.5 bar

Step-by-step explanation:

Nastasia [14]3 years ago

4 0

Answer:

.5 bar

Step-by-step explanation:

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Someone help me please !!!

KIM [24]

Answer:

1. 10

2. 12

3. Sqrt 130

4. Sqrt 45

Step-by-step explanation:

To find the missing side of a right triangle, use the Pythagorean Theorem. The Pythagorean Theorem is $a^2+b^2=c^2$ where a and b are the legs with a being the smallest and c is the hypotenuse.

1. a=6, b=8, c=?

$6^2+8^2=c^2\\36+64=c^2\\100=c^2\\10=c$

2. a=5, b=?, c=13

$5^2+b^2=13^2\\25+b^2=169\\169-25=b^2\\144=b^2\\12=b$

3. a=7, b=9, c=?

$7^2+9^2=c^2\\49+81=c^2\\130=c^2\\\sqrt{130}=c$

4. a=2, b=?, c=7

$2^2+b^2=7^2\\4+b^2=49\\49-4=b^2\\45=b^2\\\sqrt{45}=b$

5 0

2 years ago

What is 18÷15÷12÷9= tell me what is this answer pleas tell me

Alla [95]

18/15/12/9 = 0.0111111111111

Have a great evening. I hope this helped! :)

4 0

2 years ago

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PLEASE HELP ME IM BEGGING YOU!!!<br> FIND THE VALUE OF X

Korvikt [17]

84 I'm sure it's that I did it before

8 0

3 years ago

Read 2 more answers

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

2 years ago

What is slope intercept form?

emmainna [20.7K]

Answer:

Step-by-step explanation:

The equation of the line is written in the slope-intercept form, which is: y = mx + b, where m represents the slope and b represents the y-intercept. In our equation, y = 6x + 2, we see that the slope of the line is 6.

Hope this helps :)

5 0

1 year ago

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