probability of one go on vacation and one does not go on vacation is 0.2356 and probability none of them go on vacation is 0.1444
According to a survey, 62% of americans go on vacation each .
two americans are chosen from a group of 100 americans.
what is the probability that one or both of the people chosen does not go on vacation each ?
62% americans go on vacation t
hen 38% americans does not go on vacation
Total group of americans is 100
out of 100 americans 62 go on vacation and 38 does not go on vacation
probability of one go on vacation and one does not go on vacation
= 0.62*0.38
=0.2356
probability none of them go on vacation
= 0.38*0.38
=0.1444
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Answer:
0
Step-by-step explanation:
f(6)= -6×2+2×6
f(6)= -12+12 = 0
Answer:
(-6,8)
Step-by-step explanation:
2x + 9y = 60
-9x + y = 62 --> y = 9x + 62 --> 2x + 9(9x + 62) = 60 -->
2x+ 81x + 558 = 60 -->
83x + 558 = 60 -->
83x = -498 -->
x = -6 -->
y = 9(-6) + 62 -->
y = 8
Answer:
Step-by-step explanation:
Let c represent the total cost of booking either Uber or Lyft for x miles.
Let m represent the number of miles ridden with either Uber or Lyft.
Uber charges $0.80 per mile and a booking fee of $2.30. This means that the total cost of riding with Uber for m miles would be
c = 2.30 + 0.8m - - - - - - - - - -1
Lyft charges $1.07 per mile with no booking fee. This means that the total cost of riding with Lyft for m miles would be
c = 1.07m - - - - - - - - - -2
Equation 1 and equation 2 are the system of equations that bests models this situation
Answer:
90 cubic inches
Step-by-step explanation:
