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2 years ago

?.4 + 7 = ? +16

Mathematics

1 answer:

mr Goodwill [35]2 years ago

5 0

Answer:

Step-by-step explanation:

(? * 4) + 7 = ? + 16

-? -? (subtract a "?" on both sides)

4? - ? + 7 = 16

3? + 7 = 16

-7 -7 (subtract 7 on both sides)

3? = 9

/3 /3 (divide by 3 on both sides)

? = 3

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Helpppppp meeee please and thank you

Allisa [31]

Answer:

Yes, by SAS

Step-by-step explanation:

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3 years ago

An items is regularly priced at $20. Keisha bought it on sale for 40% off the regular price. How much did Keisha pay?

nirvana33 [79]

Answer:

Kiesha paid $12.

Step-by-step explanation:

40% of 20 is 8. So you subtract 8 from 20 and that gives you the amount she paid.

6 0

2 years ago

2. A parent pledged $0.50 per lap in a walk-thon at school.

Readme [11.4K]

But how many laps did she walk

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3 years ago

Select the curve generated by the parametric equations. Indicate with an arrow the direction in which the curve is traced as t i

bixtya [17]

Answer:

length of the curve = 8

Step-by-step explanation:

Given parametric equations are x = t + sin(t) and y = cos(t) and given interval is

−π ≤ t ≤ π

Given data the arrow the direction in which the curve is traces means

the length of the curve of the given parametric equations.

The formula of length of the curve is

$\int\limits^a_b {\sqrt{\frac{(dx}{dt}) ^{2}+(\frac{dy}{dt}) ^2 } } \, dx$

Given limits values are −π ≤ t ≤ π

x = t + sin(t) ...….. (1)

y = cos(t).......(2)

differentiating equation (1) with respective to 'x'

$\frac{dx}{dt} = 1+cost$

differentiating equation (2) with respective to 'y'

$\frac{dy}{dt} = -sint$

The length of curve is

$\int\limits^\pi_\pi {\sqrt{(1+cost)^{2}+(-sint)^2 } } \, dt$

$\int\limits^\pi_\pi \, {\sqrt{(1+cost)^{2}+2cost+(sint)^2 } } \, dt$

on simplification , we get

here using sin^2(t) +cos^2(t) =1 and after simplification , we get

$\int\limits^\pi_\pi \, {\sqrt{(2+2cost } } \, dt$

$\sqrt{2} \int\limits^\pi_\pi \, {\sqrt{(1+1cost } } \, dt$

again using formula, 1+cost = 2cos^2(t/2)

$\sqrt{2} \int\limits^\pi _\pi {\sqrt{2cos^2\frac{t}{2} } } \, dt$

Taking common $\sqrt{2}$ we get ,

$\sqrt{2}\sqrt{2} \int\limits^\pi _\pi ( {\sqrt{cos^2\frac{t}{2} } } \, dt$

$2(\int\limits^\pi _\pi {cos\frac{t}{2} } \, dt$

$2(\frac{sin(\frac{t}{2} }{\frac{t}{2} } )^{\pi } _{-\pi }$

length of curve = $4(sin(\frac{\pi }{2} )- sin(\frac{-\pi }{2} ))$

length of the curve is = 4(1+1) = 8

<u>conclusion</u>:-

The arrow of the direction or the length of curve = 8

7 0

3 years ago

Add one set of parenthesis to make the following equation true<br> 25 - 8 - 2 = 19

amid [387]

An easy way to do this is to do trial and error.

All possible places to put the bracket:

a) (25 - 8) - 2 = 19 But since BEDMAS goes from left to right with Addition and Subtraction, the equation is unaffected.
b) 25 - (8 - 2) = 19
25 - 6 = 19

Therefore b) is correct.

7 0

3 years ago