4 years ago

How do you solve this?

Mathematics

1 answer:

SpyIntel [72]4 years ago

4 0

I am not a college student so I am sorry or you could ask your friends.

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Please help.... this is confusing me:0

JulsSmile [24]

Answer:

See below

Step-by-step explanation:

IN a right triangle , remember S-O-H-C-A-H-T-O-A <===memorize this!

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3 years ago

Polygon ABCD is a rectangle what is the area

Andre45 [30]

Solution:

As, You have Written Polygon ABCD is a rectangle.

It is a Four sided Polygon , having all it's interior angles equal to 90°.As well as Opposite sides are equal(AB=CD,AD=BC), equal diagonals(AC=B D).

Join any of the diagonal of Rectangle either AC or B D.

In Right Δ ABC , Right angled at B

${\text{Area (Right triangle ABC)}} =\frac{1}{2}\times AB \times BC$ ---(1)

In Right Δ ADC , Right angled at D

${\text{Area (Right triangle ABC)}} =\frac{1}{2}\times AD \times DC$ ---(2)

Adding (1) and (2) that is LHS to LHS and RHS to RHS

Ar( Δ ABC) +Ar( Δ ADC) $=\frac{1}{2}\times[ AB \times BC+ AD \times DC]\\\\=\frac{1}{2}[2 \times AB \times BC][\text{As, AB=CD, and BC=AD}]\\\\ = AB \times BC$

So, Area of Rectangle= Product of any two Adjacent Sides

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3 years ago