In this case or scenario,
the double-angle identity that should be used is the one for cosine. <span>
In totality, we shall need the following three trigonometric
identities to end up with the equality:
<span>1. cos (2a) = cos² (a) - sin² (a)
2. sin² (a) + cos² (a) = 1
<span>3. tan² (a) + 1 = sec²
(a)
<span>Using identities 1 and 2 on the left-hand side of the
equation, we get the following:</span>
1 + cos (2a) = 1 + cos² (a) - sin² (a) = 2 cos² (a) </span></span></span>
<span>
<span>Recalling that cos² (a) = 1 / sec² (a) and applying identity
3, we find the following:</span>
2 cos² (a) = 2 / sec² (a) = 2 / (1 + tan² (a)) </span>
Therefore giving us:
<span>2 cos² (a) = 2 / (1 +
tan² (a))</span>
When the ratio is 1:1, either is 1/(1+1) = 1/2 the total.
5/11 can be made into a decimal which will result as 0.45
A.) -11
b.) 31
c.) -208
d.) 12
e.) -47
f.) -28
I hope this helped (I used bedmas)
Take your graph and turn it counterclockwise 90°, 3 times (which equals 270°).
Let the horizontal line represent the x-axis and the vertical line represent the y-axis. What are the new coordinates of the image? J'(2, 6), M'(-1, 5)
Answer: C
