Answer:
150° and 210°
Step-by-step explanation:
1) according to the condition the required cosine is <0, it means the required angles are in the II-d and III-d quaters (see the attached picture no. 1);
2) it is known, that arccos(√3/2)=30°- the angle is between 0° and 90°, - but the requred angles are between 90° and 270° (see the picture no. 2), then
3) (angle)₁=180°-arccos(√3/2) and (angle)₂=180°+arccos(√3/2), then finally
(angle)₁=180°-30°=150°; (angle)₂=180°+30°=210°.
PS. note, the suggested way is not the only one.
Answer:
D. An exponential parent function
Step-by-step explanation:
The basic parent function of any exponential function is f(x) = bx, where b is the base. Using the x and y values from this table, you simply plot the coordinates to get the graphs. The parent graph of any exponential function crosses the y-axis at (0, 1), because anything raised to the 0 power is always 1.
The expression 9p − 8q for p = 4 and q = −8 is equal to 100
<h3><u>Solution:</u></h3>
Given that we have to evaluate expression for the given values of the variables
Expression is:
⇒ 9p − 8q
Given that p = 4 and q = -8
<em><u>Let us substitute the given values of p = 4 and q = -8 in given expression and evaluate it</u></em>
⇒ 9p − 8q = 9(4) - 8(-8)
⇒ 9p - 8q = 9(4) + 8(8)
Upon multiplying the terms we get,
⇒ 9p - 8q = 36 + 64 = 100
Thus the expression is equal to 100
For this case we have a function of the form:
H (t)
Where,
t: number of days
H: the daily high temperature
We have the point (0.29).
It means that the hottest day of the year had a temperature of 29 degrees.
Answer:
the hottest day of the year had a temperature of 29 degrees.
