The answer is 168 seconds.

Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
20
Step-by-step explanation:
ones= 1
tens= 10
Hundreds= 100
The difference between ones and tens is the 0. ones=1. tens=10
<u>2</u>4
The 2 is in the beginning so its the 10's place. The 4 is the second number so its in the ones place
Answer:
Blair chosen to purchase shirt from company B. Given:
Each shirt costs 3.10$
Shipping cost is 4% (0.04) of total order.
=>Total cost without shipping: 150 x 3.10 = 465$
=> Total cost with 4% of shipping: 465 + 465 x 0.04 = 483.6$
=> Total cost Blair paid for one shirt: C = 483.6/150 = 3.22$
The markup is 75% of original cost:
=> Blair can multiply the total cost for one shirt by 0.75
Blair will sell shirt with price which is equal to the sum of total cost for one shirt and markup:
=> P = 3.22 + 3.22 x 0.75 = 5.64$
Hope this helps!
:)