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Paraphin [41]
3 years ago
13

Given: NM ∥ XZ Prove: △XYZ ~ △NYM Triangles X Y Z and N Y M are shown. Triangle X Y Z is smaller and sits inside of triangle N Y

M, sharing part of 2 sides with triangle N Y M. The hypotenuses of both triangles are parallel. We know that side NM is to side XZ. If we consider side NY the transversal for these parallel lines, we create angle pairs. Using the , we can state that ∠YXZ is congruent to ∠YNM. We know that angle XYZ is congruent to angle by the reflexive property. Therefore, triangle XYZ is similar to triangle NYM by the similarity theorem.
Mathematics
1 answer:
elena-s [515]3 years ago
7 0

Answer:

Parallel

corresponding angles theorem

NYM

AA

Step-by-step explanation:  I DID IT ON EDGE! : )

We know that side NM is  _________________

✔ parallel

to side XZ. If we consider side NY the transversal for these parallel lines, we create angle pairs. Using the  _____________

✔ corresponding angles theorem

, we can state that ∠YXZ is congruent to ∠YNM. We know that angle XYZ is congruent to angle  _____________

✔ NYM

by the reflexive property. Therefore, triangle XYZ is similar to triangle NYM by the  _____________

✔ AA

 similarity theorem.

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Check the picture below.

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\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{2})\qquad 
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% slope  = m
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and for the red one hmmm (3,2) and (7,2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{2})\qquad 
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