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3 years ago

PLEASE HELP ASAP) Find the area of this parallelogram

Mathematics

1 answer:

Maurinko [17]3 years ago

6 0

Area = base * altitude = 2 * 2.9 = 5.8 cm^2

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PLEASE HELP! Since AB=1 and 1=BC, BC=AB by which property?

erastovalidia [21]

Substitution.

Here is an example.

Let x be equal to 3 and y equal to 3.

$x=3, y=3$

From this we can conclude that the values of both x and y are equal to three therefore x and y have the same value and are equal.

$x\wedge y=3\Longrightarrow x=y$

Here in your case we have:

$AB=1, BC=1 \\AB\wedge BC=1\Longrightarrow AB=BC$

Hope this helps.

r3t40

7 0

3 years ago

Eight avocados cost $4. How much do 9 avocados cost?<br><br> i am dumb

blagie [28]

I believe the answer is 4.50

5 0

3 years ago

Bert is planning to open a savings account that earns 1.6% simple interest yearly. He wants to earn exactly $240 in interest aft

RoseWind [281]

Answer:

D. $5,000

Step-by-step explanation:

The amount of money he should deposit is the principal.

The principal P can be gotten by

P = 100 I /RT

Where

I = interest

R = rate

T = Time

Given

I = $240

R = 1.6%

T = 3 yrs

P = 100 x 240 /1.6 x 3

Multiply through

= 24000/4.8

= $5000

5 0

2 years ago

The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

8 0

3 years ago

A penguin is standing 3 feet above sea level and then<br> dives down 10 feet. What is its depth?

ValentinkaMS [17]

Answer:

7 feet below sea level

Step-by-step explanation:

he was at 3 then you subtract 10 feet because he dives.

7 0

2 years ago

Read 2 more answers