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Olin [163]
3 years ago
6

A park ranger would like to clear more than 10 mi of trail. So far, he has cleared 2 mi. From now on, he can clear 3/4 mi of tra

il each hour. Drag and drop the answer into the box. What statement describes the solution to this inequality? The ranger will need to clear trail for more than 8 additional hours. The ranger will need to clear trail for more than 10 2/3 additional hours. The ranger will need to clear trail for more than 13 1/3 additional hours. The ranger will need to clear trail for more than 16 additional hours.
Mathematics
2 answers:
blondinia [14]3 years ago
3 0

Answer: The answer is (b) The ranger will need to clear trail for more than 10 2/3 additional hours.


Step-by-step explanation:  Given that a park ranger would like to clear more than 10 mi of trail. Till now, he has cleared 2 mi. From now on, he can clear 3/4 mi of trail each hour.

Since 2 mi of the trail has already been cleared, so the trail that is left to be cleared = 10 - 2 = 8 mi.

Let, the park ranger will work for 'x' more hours. So, we have

\dfrac{3}{4}\times x=8\\\\\Rightarrow 3x=32\\\\\Rightarrow x=\dfrac{32}{3}\\\\\Rightarrow x=10\dfrac{2}{3}.

Thus, the park ranger will need to work for 10 2/3 more hours.

Hence, the correct option is (b) The ranger will need to clear trail for more than 10 2/3 additional hours.


polet [3.4K]3 years ago
3 0

Answer:

B

Step-by-step explanation:

your awesome I'm awesome i think we have a connection so if you don't mind <em>crown please</em>

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\frac{1}{5}*2 = \frac{2}{5}*60pages = 24pages

<em>hope this helps, good luck :)</em>

8 0
3 years ago
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3 years ago
How does f(x) = 3 ^x change over the interval x = 4 to x= 5
zloy xaker [14]

Answer:

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6 0
3 years ago
Please help! Correct answer only, please! Consider the following information matrices for the price of clothing at a clothing st
ololo11 [35]

Answer: b) Large blue t-shirt & Medium RC jeans

<u>Step-by-step explanation:</u>

The subscript numbers attached to the matrix letter represents the:

ROW, COLUMN

A=\left[\begin{array}{ccc}a_{1,1}&a_{1, 2}&a_{1, 3}\\a_{2,1}&a_{2, 2}&a_{2, 3}\\a_{3,1}&a_{3, 2}&a_{3, 3}\end{array}\right] \qquad B=\left[\begin{array}{ccc}a_{1,1}&b_{1, 2}&b_{1, 3}\\b_{2,1}&b_{2, 2}&b_{2, 3}\\b_{3,1}&b_{3, 2}&b_{3, 3}\end{array}\right]\\

A₁,₃ = 1st row, 3rd column

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8 0
3 years ago
How do you solve this system of linear equation by substitution <br><br>x-3y=-12<br>y=2x+9
Ainat [17]
Finding x:
If y=2x+9, substitute y into the equation x-3y=-12.
You will get:  x-3(2x+9)=-12
Now, distribute:  x-6x-27=-12
Add like terms:  -5x-27=-12
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Now, substitute this value of x into the equation to find y:  y=2(-3)+9
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Add:  y=3

Here is the solution:  (x,y)=(-3,3)

Hope this explanation helped!




6 0
3 years ago
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