Answer:
b
Step-by-step explanation:
In general
Given
y = f(x) then y = f(Cx) is a horizontal stretch/ compression in the x- direction
• If C > 1 then compression
• If 0 < C < 1 then stretch
Consider corresponding points on the 2 graphs
(2, 2 ) → (4, 2 )
(4, - 2 ) → (8, - 2 )
Indicating a stretch in the x- direction.
y = f(
) with C = 
, that is 0 < C < 1
stretches the graph in the x- direction by a factor of 2
Thus
y = f( ) → b
Answer:
There are 8 dimes there.
Step-by-step explanation:
This question is solved used a system of equations.
I am going to say that:
x is the number of nickels.
y is the number of dimes.
19 coins
This means that x + y = 19.
A nickel is worth $0.05. A dime is worth $0.1. The total of these coins is $1.35. So
0.05x + 0.1y = 1.35
How many dimes are there?
We have to find y.
From the first equation: x = 19 - y.
Replacing in the second:
0.05(19 - y) + 0.1y = 1.35
0.95 - 0.05y + 0.1y = 1.35
0.05y = 0.4
y = 0.4/0.05
y = 8
There are 8 dimes there.
Answer:
<em>9%</em>
Step-by-step explanation:
Original rectangle: 100 cm by 200 cm
Original area: 100 cm * 200 cm = 20,000 cm^2
Reduced by 70%, the measures are now 30% of they they were.
30% of 100 cm = 30 cm
30% of 200 cm = 60 cm
New area: 30 cm * 60 cm = 1800 cm^3
New area equals what percent of original area?
1800/20,000 * 100 = 9%
28. Surface Area
This is some sort of house-like model so for every face we see there's a congruent one that's hidden. We'll just double the area we can see.
Area = 2 × ( [14×9 rectangle] + 2[15×9 rectangle]+[triangle base 14, height 6] )
Let's separate the area into the area of the front and the sides; the front will help us for problem 29.
Front = [14×9 rectangle] + [triangle base 14, height 6]
= 14×9 + (1/2)(14)(6) = 14(9 + 3) = 14×12 = 168 sq ft
OneSide = 2[15×9 rectangle] = 30×9 = 270 sq ft
Surface Area = 2(168 + 270) = 876 sq ft
Answer: D) 876 sq ft
29. Volume of an extruded shape is area of the base, here the front, times the height, here 15 feet.
Volume = 168 * 15 = 2520 cubic ft
Answer: D) 2520 cubic ft
Answer: It does not matter whether you multiply the radicands or simplify each radical first. You multiply radical expressions that contain variables in the same manner. As long as the roots of the radical expressions are the same, you can use the Product Raised to a Power Rule to multiply and simplify.
Step-by-step explanation:
