Answer: yes
Step-by-step explanation:
There is not answer to your equation so technically anything could be X
(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ = 
= 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
Answer:
y=4x
Step-by-step explanation:
it's enough to use first column (x=6, y=24). Inserting this data into equation y=kx, we can calculate k.
24=k*6
6k = 24
k = 24/6
k = 4
<span> here
7 7/8
= [ (8*7) + 7 ] / 8
= (56 + 7) / 8
=63 / 8
similarly,
3 1/4
=[ (4*3) + 1] / 4
= (12 + 1) / 4
= 13/4
----------------------------
now put the values
7 7/8 - 3 1/4
= 63/8 - 13/4
here, take LCM of 8 & 4 which is 8.
now,
[ (1*63) - (2 * 13) ] / 8
= (63 - 26) / 8
= 37/8
= 4 5/8........................[ here, divide 37 by 8 which gives reminder as 5 and divisible value as 4 ]</span>
C strong negative is the answer
